Calculate the kinetic energy of a 0.300 kg baseball thrown at a velocity of 34 m/s. 173 J 390 J 490 J 590 J 920 J

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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**Question:**

Calculate the kinetic energy of a 0.300 kg baseball thrown at a velocity of 34 m/s.

**Options:**

- ○ 173 J
- ○ 390 J
- ○ 490 J
- ○ 590 J
- ○ 920 J

**Explanation:**

Kinetic energy (KE) is calculated using the formula:

\[ KE = \frac{1}{2} mv^2 \]

Where:
- \( m \) is the mass in kilograms (kg)
- \( v \) is the velocity in meters per second (m/s)

Substituting the given values:

\[ KE = \frac{1}{2} \times 0.300 \, \text{kg} \times (34 \, \text{m/s})^2 \]
\[ KE = \frac{1}{2} \times 0.300 \times 1156 \]
\[ KE = 0.150 \times 1156 \]
\[ KE = 173.4 \, \text{J} \]

Thus, the correct answer is 173 J.
Transcribed Image Text:**Question:** Calculate the kinetic energy of a 0.300 kg baseball thrown at a velocity of 34 m/s. **Options:** - ○ 173 J - ○ 390 J - ○ 490 J - ○ 590 J - ○ 920 J **Explanation:** Kinetic energy (KE) is calculated using the formula: \[ KE = \frac{1}{2} mv^2 \] Where: - \( m \) is the mass in kilograms (kg) - \( v \) is the velocity in meters per second (m/s) Substituting the given values: \[ KE = \frac{1}{2} \times 0.300 \, \text{kg} \times (34 \, \text{m/s})^2 \] \[ KE = \frac{1}{2} \times 0.300 \times 1156 \] \[ KE = 0.150 \times 1156 \] \[ KE = 173.4 \, \text{J} \] Thus, the correct answer is 173 J.
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