
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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![**Question:**
Calculate the kinetic energy of a 0.300 kg baseball thrown at a velocity of 34 m/s.
**Options:**
- ○ 173 J
- ○ 390 J
- ○ 490 J
- ○ 590 J
- ○ 920 J
**Explanation:**
Kinetic energy (KE) is calculated using the formula:
\[ KE = \frac{1}{2} mv^2 \]
Where:
- \( m \) is the mass in kilograms (kg)
- \( v \) is the velocity in meters per second (m/s)
Substituting the given values:
\[ KE = \frac{1}{2} \times 0.300 \, \text{kg} \times (34 \, \text{m/s})^2 \]
\[ KE = \frac{1}{2} \times 0.300 \times 1156 \]
\[ KE = 0.150 \times 1156 \]
\[ KE = 173.4 \, \text{J} \]
Thus, the correct answer is 173 J.](https://content.bartleby.com/qna-images/question/500c0e80-687a-4e1b-8f8e-54233bb713dd/11d69a82-8c02-4bec-bca1-5321bd77f723/6jgdjp_thumbnail.png)
Transcribed Image Text:**Question:**
Calculate the kinetic energy of a 0.300 kg baseball thrown at a velocity of 34 m/s.
**Options:**
- ○ 173 J
- ○ 390 J
- ○ 490 J
- ○ 590 J
- ○ 920 J
**Explanation:**
Kinetic energy (KE) is calculated using the formula:
\[ KE = \frac{1}{2} mv^2 \]
Where:
- \( m \) is the mass in kilograms (kg)
- \( v \) is the velocity in meters per second (m/s)
Substituting the given values:
\[ KE = \frac{1}{2} \times 0.300 \, \text{kg} \times (34 \, \text{m/s})^2 \]
\[ KE = \frac{1}{2} \times 0.300 \times 1156 \]
\[ KE = 0.150 \times 1156 \]
\[ KE = 173.4 \, \text{J} \]
Thus, the correct answer is 173 J.
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