Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Calculate the heat of reaction (in kJ) when 40.7 mL of 1.2 M nitric acid reacts with 49.1 mL of 0.75 M sodium hydroxide.

attached below is the equation needed

When one mole of sodium hydroxide reacts, 57.3 kJ of heat are released. \[ \text{HNO}_3 + \text{NaOH} \rightarrow \text{NaNO}_3 + \text{H}_2\text{O} \qquad \Delta H_{\text{rxn}} = -57.3 \, \text{kJ/mol} \] The amount of reactants used is the molar equivalent to that given in the balanced equation.
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Transcribed Image Text:When one mole of sodium hydroxide reacts, 57.3 kJ of heat are released. \[ \text{HNO}_3 + \text{NaOH} \rightarrow \text{NaNO}_3 + \text{H}_2\text{O} \qquad \Delta H_{\text{rxn}} = -57.3 \, \text{kJ/mol} \] The amount of reactants used is the molar equivalent to that given in the balanced equation.
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