Calculate the formal concentration in molarity of a sodium acetate solution prepared by diluting 90.0 mL of a solution containing 25.0 ppmsodium acetate (NaC2H302) 82.03 g/mol to a total of 0.500 liters of solution.1.0275x10 Molar2. 06 10 x 10- Molar3. 0137x 10-6 Molar4 05.48 x 10-P MolarPreviousNextコ ECSTEAere to searchhpFor Weak Acids Titrated with aic Acid Titrated with NaOHcontinuedacid (pKa = 4.757).12EquivalencePoirt10g base.PHfollows a curve similar in shane tnn curve, but the eauiun6.pK,

Using equation of dilution we can find final concentration of solution.

Calculate the formal concentration in molarity of a sodium acetate solution prepared by diluting 90.0 mL of a solution containing 25.0 ppm sodium acetate (NAC2H302) 82.03 g/mol to a total of 0.500 liters of solution. 1 0275x10 Molar 2. 06 10 x 10-4 Molar 3. 0137x 10-6 Molar 4 05.48 x 10-P Molar

Calculate the formal concentration in molarity of a sodium acetate solution prepared by diluting 90.0 mL of a solution containing 25.0 ppm sodium acetate (NAC2H302) 82.03 g/mol to a total of 0.500 liters of solution. 1 0275x10 Molar 2. 06 10 x 10-4 Molar 3. 0137x 10-6 Molar 4 05.48 x 10-P Molar

Introductory Chemistry For Today

8th Edition

ISBN:9781285644561

Author:Seager

Publisher:Seager

Chapter7: Solutions And Colloids

Section: Chapter Questions

Problem 7.31E

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Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

Calculate the formal concentration in molarity of a sodium acetate solution prepared by diluting 90.0 mL of a solution containing 25.0 ppm
sodium acetate (NaC2H302) 82.03 g/mol to a total of 0.500 liters of solution.
1.0275x10 Molar
2. 06 10 x 10- Molar
3. 0137x 10-6 Molar
4 05.48 x 10-P Molar
Previous
Next
コ E
CS
TEA
ere to search
hp
For Weak Acids Titrated with a
ic Acid Titrated with NaOH
continued
acid (pKa = 4.757).
12
Equivalence
Poirt
10
g base.
PH
follows a curve similar in shane tn
n curve, but the eauiun
6.
pK,

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