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Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Calculate the final concentration of a solution that is made by dissolving 14.8 g of solid sodium hydroxide in
600.0 mL of solution.
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- A potassium iodide solution is made by mixing 3.241 grams of potassium iodide and mixing it into 248.2 mL of water. Calculate the molarity of this solution.arrow_forwardCalculate the molarity of a solution prepared by adding 17.3 g sodium sulfate to a total volume of 864 mL.arrow_forwardA 11.5 g sample of an aqueous solution of hydroiodic acid contains an unknown amount of the acid. If 12.2 mL of 0.898 M sodium hydroxide are required to neutralize the hydroiodic acid, what is the percent by mass of hydroiodic acid in the mixture? % by massarrow_forward
- If 26.8 g of KBr (MM = 119.00 g/ mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the concentration of KBr in the resulting solution?arrow_forwardCalculate the molarity of the two solutions. The first solution contains 0.400 mol0.400 mol of NaOHNaOH in 2.30 L2.30 L of solution. The second solution contains 18.9 g18.9 g of NaClNaCl in 731 mL731 mL of solution.arrow_forwardCalculate the molarity of the two solutions. The first solution contains 0.600 mol0.600 mol of NaOHNaOH in 1.95 L1.95 L of solution. The second solution contains 20.9 g20.9 g of NaClNaCl in 709 mL709 mL of solution.arrow_forward
- A solution is prepared by dissolving 18.1 g ammonium sulfate in enough water to make 120.0 mL of stock solution. A 10.00-mL sample of this stock solution is added to 40.00 mL of water. Calculate the concentration of ammonium ions and sulfate ions in the final solution. Assume that the volumes are additive.arrow_forwardcalculate the concentration of solution prepared by adding 1.025 g of sodium chloride to enough water to make 100.00 mL of solution.arrow_forwardA solution is prepared by dissolving 15.9 g ammonium sulfate in enough water to make 100.0 mL of a stock solution. A 10.00 mL portion of this stock solution is added to 50.00 mL of water. Calculate the concentration of ammonium ions in the final solution.arrow_forward
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