Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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I don’t understand this question. Professor told me to show my work if possible. Thank you in advance.
**Exercise 12.30: Calculating Light Efficacy** Calculate the efficacy for the following lights: (a) Sylvania accent LED light, which uses 2 watts and produces 60 lumens. (b) Sylvania 40 W CFL, which uses 9 watts and produces 495 lumens. **Explanation:** Light efficacy is a measure of how efficiently a light source produces visible light, expressed in lumens per watt (lm/W). To calculate the efficacy, use the formula: \[ \text{Efficacy} = \frac{\text{Lumens}}{\text{Watts}} \] - For the Sylvania accent LED light: \[ \text{Efficacy} = \frac{60 \text{ lumens}}{2 \text{ watts}} = 30 \, \text{lm/W} \] - For the Sylvania 40 W CFL: \[ \text{Efficacy} = \frac{495 \text{ lumens}}{9 \text{ watts}} = 55 \, \text{lm/W} \]
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Transcribed Image Text:**Exercise 12.30: Calculating Light Efficacy** Calculate the efficacy for the following lights: (a) Sylvania accent LED light, which uses 2 watts and produces 60 lumens. (b) Sylvania 40 W CFL, which uses 9 watts and produces 495 lumens. **Explanation:** Light efficacy is a measure of how efficiently a light source produces visible light, expressed in lumens per watt (lm/W). To calculate the efficacy, use the formula: \[ \text{Efficacy} = \frac{\text{Lumens}}{\text{Watts}} \] - For the Sylvania accent LED light: \[ \text{Efficacy} = \frac{60 \text{ lumens}}{2 \text{ watts}} = 30 \, \text{lm/W} \] - For the Sylvania 40 W CFL: \[ \text{Efficacy} = \frac{495 \text{ lumens}}{9 \text{ watts}} = 55 \, \text{lm/W} \]
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