Calculate the discharge through a venturimeter connected to a differential manometer. The liquid present in the manometer is taken as mercury and the fluid flowing through he venturimeter is water. The difference between the level of mercury in 2 limbs of hanometer is 30 mm. The diameter of inlet is 20cm and the ratio of the area of inlet and hroat is 4. Assume the coefficient of discharge as 0.96. ) 0.0211m/sec )0.0325 m/sec ) 0.0289 m/sec ) 0.0363 m /sec

E9

(Bernoulli/continuity/Pitot tube) Two Pitot tubes and two static pressure taps are placed in the pipe contraction shown in the figure below. The flowing fluid is water, and viscous effects are negligible. Determine the two manometer readings, h and H. V=1.7 ft/s h = H= 6.4 in. Air ↓ SG= 1.10 ft ft TH 3.8 in.

600mm water diameter 300mm 1. diameter 02 150mm Mercury (SG = 13.6) A venturi meter with diameter of 300mm is attached to a 600mm main pipe and has its axis inclined downward as shown. a) Discharge if head loss is neglected is Blank 1 cu.m./s b) Discharge if head loss is 500mm from point 1 to 2 is Blank 2 cu.m./s c) Coefficient of discharge is Blank 3 The manometer shows a deflection of 15cm of mercury (SG =13.6). If the flowing fluid is water and direction is from 1 to 2, determine the