Calculate the development length at simply supported edge in mm from the following information: M25 and Fe 415 steel is used Tbd =1.4 MPa V = 30 KN and M = 16.076 KNm Side way clear spacing is 50 mm d = 120 mm and width of support which are under compression is 300 mm

Calculate the development length at simply supported edge in mm from the following information: M25 and Fe 415 steel is used Tbd =1.4 MPa V = 30 KN and M = 16.076 KNm Side way clear spacing is 50 mm d = 120 mm and width of support which are under compression is 300 mm

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter6: Beam–columns

Section: Chapter Questions

Problem 6.9.2P

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Concept explainers

Types and properties of steel

Steel is an alloy of iron. It is formed by heating iron and combining carbon (0.1-1.7%) with it and minor amounts of other elements such sulfur, chromium, manganese, nickel, etc. Thousands of steel grades have been published, registered, or regulated around the world, each with its chemical composition, and special numbering systems have been devised in various countries to classify the vast number of alloys.

Question

Calculate the development length at simply supported edge in mm from the following information:
M25 and Fe 415 steel is used
Tbd =1.4 MPa
V = 30 KN and M = 16.076 KNm
Side way clear spacing is 50 mm
d = 120 mm and width of support which are under compression is 300 mm

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