Calculate the concentration of an aqueous solution of Ca(OH)2Ca(OH)2 that has a pHpH of 11.52. Express your answer using two significant figures.

An analytical chemist weighs out 0.138 g of an unknown monoprotic acid into a 250 mL volumetric flask and dilutes to the mark with distilled water. He then titrates this solution with 0.0600M NaOH solution. When the titration reaches the equivalence point, the chemist finds he has added 25.5 mL of NaOH solution. Calculate the molar mass of the unknown acid. Round your answer to 3 significant digits. 0 mol X S 629 OL A

it is time for the titration.  You measure 15.0 mL of the H2C2O4 solution with a 100-mL graduated cylinder and add it to a 125-mL Erlenmeyer flask.  Then you add two drops of the indicator, phenolphthalein, to the oxalic acid solution in the flask.  You dispense the NaOH solution from the buret into the flask (while swirling the flask) until you reach the endpoint.  At the endpoint, the solution in the flask turns light pink.  You repeat the titration two additional times for a total of three trials.  H2C2O4 (aq) + 2 NaOH (aq) --> Na2C2O4 (aq) + 2 H2O (l)                                                (I)              (II)                (III) Volume of H2C2O4 used  15.00 mL   15.00 mL   15.00 mL Initial Buret Reading        0.00 mL    0.05 mL         0.10 mL Final Buret Reading           14.45 mL     14.38 mL    15.40 mL Volume NaOH used           ________mL          ________mL        ______mL Moles NaOH                     _______M      ________M    _________M…

An analytical chemist weighs out 0.181 g of an unknown diprotic acid into a 250 mL volumetric flask and dilutes to the mark with distilled water. She then titrates this solution with 0.1700 M NaOH solution. When the titration reaches the equivalence point, the chemist finds she has added 15.9 mL of NaOH solution. Calculate the molar mass of the unknown acid. Be sure your answer has the correct number of significant digits. ol. g mol Ar

A chemistry student weighs out 0.159 g of ascorbic acid (H,C,H,0), a diprotic acid, into a 250. mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.0800M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the final equivalence point. Be sure your answer has the correct number of significant digits. mL

A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 13.mg of oxalic acid H2C2O4, a diprotic acid that can be purchased inexpensively in high purity, and dissolves it in 250.mL of distilled water. The student then titrates the oxalic acid solution with her sodium hydroxide solution. When the titration reaches the equivalence point, the student finds she has used 11.9mL of sodium hydroxide solution. Calculate the molarity of the student's sodium hydroxide solution. Round your answer to 2 significant digits.

An analytical chemist weighs out 0.280g of an unknown diprotic acid into a 250mL volumetric flask and dilutes to the mark with distilled water. She then titrates this solution with 0.1400M NaOH solution. When the titration reaches the equivalence point, the chemist finds she has added 26.7mL of NaOH solution. Calculate the molar mass of the unknown acid. Round your answer to 3 significant digits.

Calculate the number of H+(aq) ions in 1.4 mL of pure water at 25 ° C. Express your answer using two significant figures.

You are performing an experiment in lab that involves the titration of a H2SO4 solution. You titrate the acidic solution with 0.5166 M NaOH and the equivalence point is reached by the addition of 21.76 mL of NaOH solution. Using the balanced equation below, calculate the moles of H2SO4 in the flask. Do NOT include units or write the answer in scientific notation. 2NaOH(aq) + H2SO4(aq) → 2H2O(l) + Na2SO4(aq)

Write a balanced net-ionic equation for the neutralization reaction between CH3COOH (aq) and Ba(OH)2 (aq). 2 CH3COOH (aq) + Ba(OH)2 (aq) --> 2 CH3COO- (aq) + 2 H₂O (1) + Ba²+ (aq) 2 CH3COOH (aq) + 2 OH" (aq) --> 2 CH3COO(aq) + 2 H₂O (1) CH3COOH (aq) + OH" (aq) --> CH3COO (aq) + H₂0 (1) OH(aq) + OH- (aq) --> H₂O (1) 2 H (aq) + 2 OH- (aq) --> 2 H₂O (1)