### Momentum and ImpulseMomentum \((p)\) and impulse \((J)\) are important concepts in physics, especially in the context of collisions and interactions between objects.#### Equations1. **Momentum Equation:** \[ p = mv \] - \(p\) = momentum - \(m\) = mass - \(v\) = velocity2. **Impulse Equation:** \[ J = Ft \] - \(J\) = impulse - \(F\) = force - \(t\) = time3. **Alternate Form of Impulse Equation:** \[ Ft = m \Delta v \] - \( \Delta v \) = change in velocity#### Example ProblemCalculate the change in momentum of a 0.5 kg ball that strikes the floor at 15 m/s and bounces back up at 12 m/s.### Solution1. **Identify Initial and Final Velocities:** - Initial velocity \( v_i = 15 \, \text{m/s} \) (downward, so it can be considered negative if upward is positive) - Final velocity \( v_f = 12 \, \text{m/s} \) (upward, positive direction)2. **Calculate the Change in Velocity:** \[ \Delta v = v_f - v_i \] Since the ball changes direction, we should consider the direction as well: \[ \Delta v = 12 \, \text{m/s} - (-15 \, \text{m/s}) = 12 \, \text{m/s} + 15 \, \text{m/s} = 27 \, \text{m/s} \]3. **Calculate the Change in Momentum:** \[ \Delta p = m \Delta v \] Given \( m = 0.5 \, \text{kg} \): \[ \Delta p = 0.5 \, \text{kg} \times 27 \, \text{m/s} = 13.5 \, \text{kg} \cdot \text{m/s} \]So, the change in momentum of the ball is \( 13

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Description: ### Momentum and ImpulseMomentum \((p)\) and impulse \((J)\) are important concepts in physics, especially in the context of collisions and interactions between objects.#### Equations1. **Momentum Equation:** \[ p = mv \] - \(p\) = momentum

Given, mass of the ball, m = 0.5 kg speed of the ball (towards the floor), u = 15 m/s speed after…

Answered: Calculate the change in momentum of a…

Science

Physics

Calculate the change in momentum of a 0.5 kg ball that strikes the floor at 15 m/s and bounces back up at 12 m/s.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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I. A lump of clay (m = 3.01 kg) is thrown towards a wall at speed v = 3.15 m/s. The lump sticks to the wall. (a) What kind of collision is it? Is momentum conserved during this collision? Why or why not? (b) Calculate the impulse imparted on the lump by the wall. (c) Calculate percent of initial kinetic energy lost during this collision. II. Same lump is thrown towards the same wall, but this time it bounces off the wall at speed of 3.15 m/s. (a) What kind of collision is it? Is momentum conserved during this collision? Why or why not? (b) Calculate the impulse imparted on the lump by the wall. (c) Calculate percent of initial kinetic energy lost during this collision. III. Same lump is thrown towards the same wall, but this time it bounces off the wall at speed of 2.24 m/s. (a) What kind of collision is it? Is momentum conserved during this collision? Why or why not? (b) Calculate the impulse imparted on the lump by the wall. (c) Calculate percent of initial kinetic…