Calculate the boiling and freezing points of 0.221 mol/kg aqueous solutions of NaCl and of CaCl,.К,(Н-0) %3 0.520 °C/mK{(H2O) = 1.86 °C/mТь (Н-0) — 100.00 °CTf (H2O) = 0.00 °CT(NaCl) solution:°CТЬ(СаCl>) solution:°CT{(NaCl) solution:°CT(CaCl2) solution:°CSubmitShow Approach Show Tutor Steps

Given data,molality of NaCl=0.221mol/Kgmolality of…

Calculate the boiling and freezing points of 0.221 mol/kg aqueous solutions of NaCl and of CaCl2. К,Н,0) — 0.520 °C/m K(H2O) = 1.86 °C/m Ть (Н-0) %3D 100.00 °C Tf (H2O) = 0.00 °C T,(NaCl) solution: °C Tp(CaCl,) solution: °C T(NaCl) solution: °C T(CaCl,) solution: °C

Calculate the boiling and freezing points of 0.221 mol/kg aqueous solutions of NaCl and of CaCl2. К,Н,0) — 0.520 °C/m K(H2O) = 1.86 °C/m Ть (Н-0) %3D 100.00 °C Tf (H2O) = 0.00 °C T,(NaCl) solution: °C Tp(CaCl,) solution: °C T(NaCl) solution: °C T(CaCl,) solution: °C

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Calculate the boiling and freezing points of 0.221 mol/kg aqueous solutions of NaCl and of CaCl,.
К,(Н-0) %3 0.520 °C/m
K{(H2O) = 1.86 °C/m
Ть (Н-0) — 100.00 °C
Tf (H2O) = 0.00 °C
T(NaCl) solution:
°C
ТЬ(СаCl>) solution:
°C
T{(NaCl) solution:
°C
T(CaCl2) solution:
°C
Submit
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