Calculate the area of a piece of property bounded by a traverse and circular arc with the following coordinates at angle points: A (1275.11, 1356.11), B (1000.27,1365.70), C (1000.00, 1000.00), D (1450.00, 1000.00) with a circular arc of radius CD starting at D and ending at A with the curve outside the course AD. Divide the area of the lot in into two equal parts by a line through point B. List in order the lengths and azimuths of all sides for each parcel. NOTE: For this research work, use a white cartolina for your plotting, use appropriate scale and use the given format for your calculations.

1) The junctions of the square grid shown below were levelled to determine the volume of excavation necessary in the construction of a basement floor. The reduced levels of the grid points are as shown. X X X X X 185.67 186.22 187.34 187.45 188.00 X X X X X 186.33 187.03 187.22 187.56 187.90 X X 186.64 186.98 187.44 X X X X X 187.08 187.35 187.89 187.34 187.43 X X X X 187.24 187.46 188.02 187.93 187.26 The horizontal distance between the grid points is 20 m and the required formation level of the basement floor foundations is to be 178.00 m. Calculate the volume of the excavation within the grid area.

12. For a proposed new road, the cross sectional areas at different sections are as follows: Station 1+000 1+020 1+040 1+060 1+080 1+100 1+120 29.6 38.4 37.6 25.5 15.0 9.7 Area(som) 18.4 Calculate the volume enclosed between station 1+000 and 1+120 by prismoidal and end area formula.

Given the following sections: Station 3+ 080 405 3.00 3.00 Z05 +0.84 +3.50 +285 +2.12 +3.24 Station 3+ 100 7.80 200 4.00 565 +3.84 +242 +3.25 +2.50 +212 The base of road is 6m and the sideslope is 1.25:1. Find the area of the first station. Select the correct response: 31.14 m2 O 23.11 m2 O 28.52 m2 32.15 m2

2. A boundary line runs across a 75m wide road reserve as shown on the diagram below. From the data provided in the diagram calculate the bearing of the road side AC and the bearing and the length of the road side CD. 69.483m Br 138.807m 63 00"! 75.00m 166 970m 75.00m

Kindly show me the solution. Thank you.

2. Determine the enclosed area of Lot 5, shown in the figure below. Also, compute the length of the curving boundary line BC. The data for the curved boundary line BC are given: the central angle A = 41.4° and the curve radius R = 200 ft. D N S45°E 100.00 ft A S45°W 100.00 ft Lot 5 Arc N45°E 200.00 ft Chord 141.42 ft R= 200.00 ft B A = 41.4°

Given the following sections: Station 3+ 080 4.05 3.00 3.00 7.05 +0.84 +3.50 +2.85 +2.12 +3.24 Station 3+ 100 7.80 2.00 4.00 5.65 +3.84 +2.42 +3.25 +2.50 +2.12 The base of the road is 6m and the side slope is 1.25:1. Find the volume between the two stations using end area method. Select the correct response: a) 497.18 m3 b) 502.20 m3 c) 613.45 m d) 396.26 m³

help asap, 2 decimal places   An equilateral triangular track of land has a length of one of its sides equal to 3600 m long. It is required to divide the lot into 3 equal areas by a line parallel to one of the 3 sides. a.Compute the whole area of the lot.  b.Compute the length of the dividing line on the portion near the vertex. c.Compute the length of the dividing line on the second lot.

By the trapezoidal rule, find the area between a traverse line and a curved boundary, rectangular offsets being taken at intervals of 5 meters, and the values of the offsets being h1 = 3.2, h2 = 3.4, h3 = 12.8, h4 = 11.2, and h5 = 4.4.