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**Calculate the amount of energy released or absorbed in each step of the PPI reaction chain.**

Use \( E = mc^2 \) and express your answer in MeV. 

- Use \( m \) for \( ^1_1H = 1.0079 \, \text{u} \)
- \( m \) for \( ^2_1H = 2.0141 \, \text{u} \)
- \( m \) for \( ^3_2He = 3.0160 \, \text{u} \)
- \( m \) for \( ^4_2He = 4.0026 \, \text{u} \)
- \( m_e = 5.4858 \times 10^{-4} \, \text{u} \)
- \( u = 931.494013 \, \text{MeV/c}^2 \) 

*Note: There are no graphs or diagrams in this image to describe.*
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Transcribed Image Text:**Calculate the amount of energy released or absorbed in each step of the PPI reaction chain.** Use \( E = mc^2 \) and express your answer in MeV. - Use \( m \) for \( ^1_1H = 1.0079 \, \text{u} \) - \( m \) for \( ^2_1H = 2.0141 \, \text{u} \) - \( m \) for \( ^3_2He = 3.0160 \, \text{u} \) - \( m \) for \( ^4_2He = 4.0026 \, \text{u} \) - \( m_e = 5.4858 \times 10^{-4} \, \text{u} \) - \( u = 931.494013 \, \text{MeV/c}^2 \) *Note: There are no graphs or diagrams in this image to describe.*
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