Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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PROBLEM: The following are the results in the test for specific gravity of fine aggregates:
a. Mass of Oven-dry specimen in air = 502 grams
b. Mass of Pycnometer filled with water, to calibration mark = 640 grams
c. Mass of Saturated Surface-Dry Specimen = 510 grams
d. Mass of Pycnometer filled with specimen and water to calibration mark = 950 grams
Calculate the absorption, apparent specific gravity, bulk specific gravity in SSD condition, and bulk specific gravity in OD condition.
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- 4. From the given data shown in the table below, determine the effective specific gravity of aggregates. Round off to two decimal places.arrow_forwardQuartering (or splitting) means reducing sample sizes into reasonable volumes. Would you expect every after each quartering (or splitting) process, the weight of the original aggregates would be reduced to half or almost half? Why or why not? Defend your reason.arrow_forward10. A sample of coarse aggregate weighs 1072 g when oven- dried, 1091 g when saturated surface-dried, and 667.6 g when submerged. Calculate the bulk specific gravity, apparent specific gravity, and absorption.arrow_forward
- 2 Compare the advantages and disadvantages of fine and coarse aggregates.arrow_forwardFrom the given data shown in the table below, determine the effective specific gravity of aggregates. Round off to two decimal places.arrow_forwardInstruction: Please provide complete solutions and box final answers.arrow_forward
- Aggregates from three sources having the properties shown in the table below where blended at a ratio of 30:45:25 by weight. Determine the properties of the aggregate blend. (Please show me in direct solution)arrow_forwardQ.2) Answer the following question. 1- The sieve analysis below was done for which type of aggregate. Weight of sample = 2000gm Sieve size in. (mm) 3/8" 9.5 mm No.4 4.75 mm No.8 2.36 mm No.16 1.18 mm No.30 0.6 mm No.50 0.3 mm No.100 0.15 mm Pan Percent Weight retained (g) retained 0 2000*100 94 Klcc→ -2000 4032000X100 →0 358420000 360 2000 X 492-20000 72 2000 x 6² 118 982 Percent cumulative @ 4.7 > 95 20 i7-75 18 2212000x100 · 100 29 24.614 57 39 3 Percent passing 0 5 25 уз 61 86 97 317 ASTM Limit 100 95_100 80_100 40 85 25_60 10_30 2_10arrow_forwardhelp me find solutions for a,b,c,d,and earrow_forward
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