Calculate K'p for the following reaction: 3CH3OH(g) 3CO(g) + 6H2(g)

Enter your answer in the provided box. Consider the following reaction at a high temperature. Br2(g) 2Br(g) When 1.30 moles of Br2 are put in a 0.710-L flask, 1.90 percent of the Br2 undergoes dissociation. Calculate the equilibrium constant Ke for the reaction.

At 475 oC, Keq = 0.230 for the reaction: 1/3 NO2(g) + 1/3 N2O(g) (equilibrium arrows)  NO(g) (a) What is the value of Keq for the reaction NO(g)  1/3 NO2(g) + 1/3 N2O(g)?Keq =  .(b) What is the value of Keq for the reaction NO2(g) + N2O(g)  3 NO(g)?Keq =  .(c) What is the value of Keq for the reaction 3 NO(g)  NO2(g) + N2O(g)?Keq =  .

Calculate the mass of PCl5, that must be heated in a 1.0L flask at 250 oC in order to produce enough chlorine to give an equilibrium concentration,[Cl2]eq. of 0.20 mol/L? PCl5(g)  <——> PCl3(g) + Cl2(g)  Kc = 0.480

Consider the following equilibrium for which H = -114.44: 4 HCl(g) + O2(g)  2 Cl2(g) + 2 H2O(g) How will each of the following changes affect an equilibrium mixture of the 4 gases in this reaction? (a) A catalyst is added to the reaction mixture. which will happen? the equilibrium will not shift  the equilibrium will shift towards product but keq will not change the equilibrium will shift towards reactant but keq will not change     the equilibrium will shift towards product and keq will increase the equilibrium will shift towards reactant and keq will decrease (b) The total pressure of the system is increased by adding a noble gas.       (c) Cl2(g) is removed from the system.

Acetaldehyde (CH3CHO) is an important chemical both industrially and biologically.  For instance, it is a (somewhat toxic) intermediate in the body's metabolism of ethanol into acetic acid, and thus is possibly implicated in the "hungover" symptoms of someone who has had too much to drink the night before.  In aqueous solution, it establishes an equilibrium with a hydrated form, shown below. CH3CHO (aq)   +   H2O (l)   <-->  CH3CH(OH)2 (aq) You start with an aqueous sample, already at equilibrium, with the CH3CH(OH)2 (the hydrated form) at a concentration of 2.60 M.  You have no information about how much, if any, of the anhydrous form (CH3CHO) is initially in the flask.  If you add 2.0 M of CH3CHO to the reaction flask, and as the equilibrium is being restored the amount of CH3CH(OH)2 changes by 1.13 M, what is the final amount of CH3CHO?

In the reaction:        2A       ⇆                B       +      3C            For the reaction,   ΔH = -23 kcal/mol   and Keq =  26 X 10 -26   Is the reaction exothermic or endothermic?     Are products or reactants favored?     Using Le Chatelier’s Principle, what happens to the equilibrium if the concentration of C is increased?     Using Le Chatelier’s Principle, what happens to the equilibrium if the concentration of A is increased?

What is the equilibrium constant expression for the reaction:3 Fe(s) + 4 H2O (g)⟷  Fe3O4 (s) + 4 H2 (g)

After equilibrium is reached in the reaction of 6.30 g H2 with 150. g I2, analysis shows that the 1.00 L flask contains 64.0 g of HI. How many moles of H2, I2, and HI are present in this equilibrium mixture? What is the Keq for this reaction?

Consider the following equilibrium for which H = -114.44: 4 HCl(g) + O2(g)  2 Cl2(g) + 2 H2O(g) How will each of the following changes affect an equilibrium mixture of the 4 gases in this reaction?(a) O2(g)) is added to the system. which will happen? the equilibrium will not shift the equilibrium will shift toward product but Keq will not change the equilibrium will shift toward reactant but Keq will not change the equilibrium will shift toward product and Keq will increase the equilibrium will shift toward reactant and Keq will decrease   (b) The reaction mixture is cooled. the equilibrium will not shift the equilibrium will shift toward product but Keq will not change the equilibrium will shift toward reactant but Keq will not change the equilibrium will shift toward product and Keq will increase the equilibrium will shift toward reactant and Keq will decrease  (c) The volume of the reaction vessel is reduced by 50%.       (d) A catalyst is added to the reaction mixture.       (e)…