Calculate final temperature of 85 g of water heated with 1,832 J. The heat capacity of water is 4190 J/kg / C ◦ The initial temperature of water is 0 C ◦      Calculate to one decimal.

For item 42: Table D2 Determination of Specific Heat of a Metal Initial mass of metal, mm (g) Initial temperature of metal, Tm,0 (°C) Initial mass of water, mw (g) Initial temperature ofwater, Tw,0 (°C) Final Temperature of mixture, T,(°C) Experimental Specific Heat cal of metal Cexp Actual Specific Heat of cal metal Cact g.Cº. Percentage Error Copper 30 42.) 110 43.) 125 20 21.94 0.9195 % For Item 42: choices for number 42 0.9180 0.9436 0.9513 0.8154 0.8354 For item 43: choices for number 43 0.17 O 0.16 0.15 0.18 0.19

What is the standard unit of temperature in the SI? (Do not abbreviate; for example gram not g.)

In a certain region for which o = 0, µ = 2µ,, 10€, and E = J= 60 • sin(10°t – Bz) a, mA/m². Find D and H

When a material changes phase - liquid, solid, gas- heat exchange is required. This heat is called the Latent heat. is the equation where L is the Latent heat and is material specific. How much heat is required to take water (mass of .55 kg) from -20 to 20 C? L for ice to water is 33.5 * 104 J/kg. the specific heat of ice is 2090 J/(kg*C).and for water is 4186 J/(kg*C).

How much energy (in MJ) is needed to raise the temperature of 0.234 m3 of water from 15.1˚C to 76.2˚C [round your final answer to one decimal place]?   {specific heat of water = 4,180 J/(kg∙˚C); density of water = 990.1 Kg/m3}