Calculate AStot for the evaporation of 165 mol of persons sweat. Because the persons temperature doesnt change much you bu may assume a constant Tsys =-160 °C and Tsurr = 36 °C throughout the process.

Is there a difference between the melting point and the freezing point of a pure substance in a given location?  Why or why not?

How many joules are in 3245 cal?

The freezing point of ethanol, C,H,OH, is -114 °C and its boiling point ОН is 78.4 °C. Given this information, which animation best depicts the particles in a sample of ethanol at 0°C? A B C

A hydrated salt is heated to determine the mole ratio of water to salt (n).  A student heated the unknown sample twice to constant mass; while cooling, the lid did not cover the crucible.  Will number of the calculated waters of hydration (n) likely be too high, too low, of unaffected?  Briefly explain your answer.

Hi! I am unsure of how to solve this problem. Thank you!

Molecular weight of a volatile liquid A student had the following data:mass of volatile liquid: 0.317 gpressure: 1.076 atmtemperature C: 97.8volume of flask: 130.8 mLThe student calculated the molar mass to be 0.06857 g / mol which is impossible since H has a molar mass of 1.008 g / mol! The error that the student made was ... A) Not converting Celsius to Kelvin B) No errors were made.   C) This unusual compound does have a fractional molar mass less than one and is the only known compound with such a mass. D) Not converting the volume from mL to L E) Using the wrong gas constant

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The mass of the flask (in part A.1) before the sample is placed into the flask, is measured when the outside of the flask is wet. However , in part B 3., THE OUTSIDE OF THE FLASK IDS DRIED BEFORE ITS MASS IS MEASURED. The reported mass of the vapor in the flask will be less than the actual mass of the vapor. True or false

How many grams of Mg3(PO4)2 are needed to make 3.000 L of a 2.500 M solution ?  The GFW for magnesium phosphate is 262.87 g.                                                   _____________ mol                                                   (  _____________ L)(–––––––––––––––––––––––) =  ________________ mol                                              _____________ L                                                                                                          ________________ g ________________ mol  (–––––––––––––––––––––––) =  _____________ g                                                   _________________ mol