Calcium is essential to tree growth in 1990, the concentration of calcium in precipitation in Chautauqua, New York, was 0.11 milligram per liter in 2018 results in the following data 0.070 0.108 0.120 0262 0.065 0234 What are the nut and shemative hypotheses?.. H₂ Y 0126 H₂ (Type integers or decimals Do not round) 0.067 mg A normal probability plot suggests the data could come from a population that is normally distributed A boxplot does not show any outlers. Does the sample evidence suggest that calciu concentrations have changed since 1990? Use the a-001 level of significance A random sample of 8 precipitation dates

A researcher measures the relationship between hours worked by employed students and the number of units taken during the first semester of college for each individual in a group of 25 community college students. For this study: a. If we calculate the average hours worked by these community college students, the average would be an example of a ________ statistic b. Is a sample or population being measured here? c. What kind of a research study is this? d. N/n = e. What level of measurement is the number of units taken? Step 2 – check your work! Was your answer correct? If not, please make any correction here: Step 3 - if your answer was incorrect, please write out what was wrong (skip this if you were correct) show working for each

70 adults with gum disease were asked the number of times per week they used to floss before their diagnoses. The (incomplete) results are shown below: # of times floss per week Frequency Relative Frequency Cumulative Frequency 10 10 1 0.1 17 2 10 0.1429 27 8. 0.1143 35 4 7. 0.1 42 ? 0.1286 51 6 0.1 12 0.1714 70 a. Complete the table (Use 4 decimal places when applicable) b. What is the cumulative relative frequency for flossing 2 times per week?

A survey of the opinions of property owners about a street widening project was taken to determine whether the resulting opinion was related to the distance of front footage. A randomly selected sample of 100 property owners was contacted and the results are shown below.                                                     Opinion             Front-Footage                        For                  Undecided                  Against             Under 45 feet                         12                                4                      4             45 – 120 feet                          35                                5                      30             Over 120 feet                         3                                  2                      5   What is the computed value of chi-square?   5.4787 4.9985 9.2784 7.9842 11.0355

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34 different video games showing drug use were observed. The duration times of drug use ​(in seconds) were recorded. When using this sample for a t test of the claim that the population mean is greater than 92 ​sec:   The value of df is? _____

a. What is the value of the standard error of the estimate (to 4 decima b. Test for a significant relationship by using thet test. Use a = 0.05. %3D What is the value of the t test statistic (to 2 decimals)? What is the p-value? Use Table 2 of Appendix B. Select your answer - What is your conclusion (a = 0.05)? %3D Select your answer - c. Use the F test to test for a significant relationship. Use a = 0.05.

Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 33 of the 38 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 94 of the 111 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: P1 #P2 Hy:P1 =P2 O B. Ho: P1 =P2 H1: P1 P2 H1: P1 #P2 Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? the null hypothesis. There sufficient evidence to support the claim that echinacea…

Listed below are the measured radiation absorption rates (in W/kg) corresponding to 11 cell phones. Use the given data to construct a boxplot and identify the 5-number summary. 1.16 0.61 0:87 1.27 1.46 0.73 1.09 1.04 1.48 0.52 0.63 The 5-number summary is and all in W/kg. (Use ascending order. Type integers or decimals. Do not round.)