C1. Assume a cache of 1 MB organized as 32 bytes each line. The main memory is 256 MB. a. Determine the number of blocks in main memory b. Determine how to split the address (s-r, r, w) for direct mapping. c. Determine how to split the address (s, w) for associative mapping. d. Determine how to split the address (s-d, d, w) for set-associative mapping. Assume each cache set is 4 lines of the cache.
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- Suppose a computer using direct mapped cache has 2^24 bytes of byte- addressable main memory and a cache size of 64K bytes, and each cache block contains 32 bytes. (Note: 64K = 26 * 210) a) How many blocks of main memory are there? b) What is the format of a memory address as seen by cache, i.e., what are the sizes of the tag, block, and offset fields?Suppose a computer using direct mapped cache has 232 byte of byte-addressable main memory, and a cache of 1024 blocks, where each cache block contains 32 bytes. a) How many blocks of main memory are there? b) What is the format of a memory address as seen by the cache, i.e., what are the sizes of the tag, block, and offset fields? c) To which cache block will the memory address 0x000063FA map?A digital computer has a memory unit of 64K X 16 and a cache memory of 1K words. The cache uses direct mapping with a block size of four words.i) How many bits are there in the tag, index, block and word fields of the address format?ii) How many bits are there in each word of cache, and how are they divided into functions? Include a valid bit.iii) How many blocks can the cache accommodate?
- 1. Suppose a computer has 2³2 bytes of byte-addressable main memory and a cache size of 2¹5 bytes, and each cache block contains 64 bytes. a) How many blocks of main memory are there? (_ b) How many blocks of cache memory are there? (_ c) If this cache is direct-mapped, what is the format of a memory address as seen by the cache; that is, the size of the tag field_ the size of block field and the size of the offset field_ d) If this cache is fully associative, what is the format of a memory address as seen by the cache; that is, the size of the tag field_ and the size of the offset field e) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache; that is, the size of the tag field_ the size of set field and the size of the offset fieldSuppose a computer using fully associative cache has 4G bytes of byte-addressable main memory and a cache of 512 blocks, where each cache block contains 128 bytes. a) How many blocks of main memory are there? b) What is the format of a memory address as seen by the cache, i.e., what are the sizes of the tag and offset fields? c) To which cache block will the memory address 0x018072 map?Suppose a computer using fully associative cache has 4 GB of byte-addressable main memory and a cache of 256 blocks, where each block contains 256 bytes. a) How many blocks of main memory are there? b) What is the format of a memory address as seen by the cache, i.e., what are the sizes of the tag and offset fields? c) To which cache block will the memory address 0X1A1B1C1D map?
- Q: A digital computer has a memory unit of 64k * 16 and a cache memory of 1k words. The cache uses direct mapping with a block size of 4 words. i) How many bits are there in the tag, index, block & words fields of the address formats. ii) How many bits are there in each word of cache? iii) How many blocks can the cache accommodate?Suppose a byte-addressable computer using set-associative cache has 216 bytes of main memory and a cache of 32 blocks, and each cache block contains 8 bytes.Q.) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache; that is, what are the sizes of the tag, set, and offset fields?4. Assume a cache of 32 Kbytes organized as 4 K lines of 8 bytes each. The main memory is 64 MB organized logically as 8 M blocks of 8 bytes each. a. Determine how to split the address (s-r, r, w) for direct mapping. b. Determine how to split the address (s. w) for associative mapping. c. Determine how to split the address (s-d, d, w) for set associative mapping. Assume each cache set is 4 lines of cache.
- Computer Science Consider a direct-mapped cache with 8 lines, each holding 16 bytes of data. The cache is byte-addressable and the main memory consists of 64 KB, which is also byte-addressable. Assume that a program reads 16KB of memory sequentially. Answer the following questions:a) How many bits are required for the tag, index, and offset fields of a cache address?b) What is the cache size in bytes?c) What is the block size in bytes?d) What is the total number of blocks in main memory?e) How many cache hits and misses will occur for the program, assuming that the cache is initially empty?f) What is the hit ratio?g) Give an example virtual address (in BINARY) that will be placed in cache line 5.A CPU has 32-bit memory address and a 256 KB cache memory. The cache is organized as a 4-way set associative cache with cache block size of 16 bytes. a. What is the number of sets in the cache? b. What is the size (in bits) of the tag field per cache block? c. What is the number and size of comparators required for tag matching? d. How many address bits are required to find the byte offset within a cache block? e. What is the total amount of extra memory (in bytes) required for the tag bits?3. Suppose a computer using direct mapped cache has 2^32 byte of byte-addressable main memory and a cache of 1024 bytes, where each block contains 64 bytes. a) How many blocks of main memory are there? b) How many blocks of cache are there? c) What is the format of a memory address as seen by the cache, i.e., what are the sizes of the tag, block, and offset fields? d) To which cache block will the memory address 0x23B6689A map?