C=0 N-H Benzoic acid Aniline I-Ż-

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter16: Amines
Section: Chapter Questions
Problem 16.40P
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Benzoic acid (C6H5COOH) and aniline (C6H5NH2) are
both derivatives of benzene. Benzoic acid is an acid with
Ka = 6.3 x10-5 and aniline is a base with Ka = 4.3 x10-10.

(a) What are the conjugate base of benzoic acid and
the conjugate acid of aniline? (b) Anilinium chloride
(C6H5NH3Cl) is a strong electrolyte that dissociates into
anilinium ions (C6H5NH3+) and chloride ions. Which will
be more acidic, a 0.10 M solution of benzoic acid or a 0.10
M solution of anilinium chloride? (c) What is the value of
the equilibrium constant for the following equilibrium?
C6H5COOH(aq) + C6H5NH2(aq) ⇌ C6H5COO-(aq) + C6H5NH3+(aq)

C=0
N-H
Benzoic acid
Aniline
I-Ż-
Transcribed Image Text:C=0 N-H Benzoic acid Aniline I-Ż-
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