Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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What is the answer for the last question? (Question "C") 

mol=mass (g)/ molar mass (g/mol)-> 1.46 (g)/143 (g/mol)= 0.01 mol.
84/10000 Word Li
(b) Assuming that all of the Ag* (aq) ions precipitated, calculate the original molarity of Ag+ (aq) in the solution before HC1(aq) was added.
B IU
x? X, 5 C n
equation to use-> molarity= mol / volume (L)
--->
if all the Ag precipitated we can conclude; mol AgCl=mol Ag
0.01/0.2 (L) = 0.05 M
24/10000 Word Lim
(c) The calculated concentration of Ag+(ag) from the student's data is higher than the actual concentration of the original solution. The student claims that the calculated concentration is too high becaus
the original solution contained some Na+ (aq) impurities that resulted in some NaCl(s) precipitating along with the AgC1(s). Do you agree or disagree? Justify your answer.
В I U
x x, 5 Ć
X2
Ω
G,
0/10000 Word Limit
After the experiment, the student learns that the precipitate, AgCl(s), is slightly soluble in water. To determine the solubility, the student mixes a sample of the precipitate with warm, distilled water to make a
saturated solution. The student finds the following equation for the dissolution of AgCl(s) in water and a Ksp value at the temperature of the water.
AgCl(s) 2 Ag (aq) + Cl¯ (aq)
Ksp = 4.0 × 10-10
(d) Calculate [Ag+lin the student's solution
II
II
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Transcribed Image Text:mol=mass (g)/ molar mass (g/mol)-> 1.46 (g)/143 (g/mol)= 0.01 mol. 84/10000 Word Li (b) Assuming that all of the Ag* (aq) ions precipitated, calculate the original molarity of Ag+ (aq) in the solution before HC1(aq) was added. B IU x? X, 5 C n equation to use-> molarity= mol / volume (L) ---> if all the Ag precipitated we can conclude; mol AgCl=mol Ag 0.01/0.2 (L) = 0.05 M 24/10000 Word Lim (c) The calculated concentration of Ag+(ag) from the student's data is higher than the actual concentration of the original solution. The student claims that the calculated concentration is too high becaus the original solution contained some Na+ (aq) impurities that resulted in some NaCl(s) precipitating along with the AgC1(s). Do you agree or disagree? Justify your answer. В I U x x, 5 Ć X2 Ω G, 0/10000 Word Limit After the experiment, the student learns that the precipitate, AgCl(s), is slightly soluble in water. To determine the solubility, the student mixes a sample of the precipitate with warm, distilled water to make a saturated solution. The student finds the following equation for the dissolution of AgCl(s) in water and a Ksp value at the temperature of the water. AgCl(s) 2 Ag (aq) + Cl¯ (aq) Ksp = 4.0 × 10-10 (d) Calculate [Ag+lin the student's solution II II
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