C++ In this exercise, we learning the concept of abstract data type (ADT). Create a structure. Name it Employee. In the Employee structure, keep 3 information about the employee. His/her name (string), numbers of hour worked (int), and his/her pay rate (float). Inside the main function create an array of struct Employee, keep the size of the array 3 to keep the simplicity of the program. As a first employee, assign your information. For second and third employee, ask all the information from the user. Then display all the information of these three employees with a calculated gross pay. Then compare the name of all three employees and show if their names are same. If none of the name is same, must show then don’t have any employees with the same name. I am adding 3 sample output for better understanding. Feel free to design your output in your way. Note: Don’t create separate data for all the employee. You must create struct Employee. Don't forget the command cin.ignore(). Sample Output: see attached images

The program is written in c++#include<string.h>#include <iostream> using namespace std; struct employee{ char name[20]; int hr; float rate,gp; void calculate_gp() { gp=hr*rate; } }; int main(){ int i,f=0; employee e[3]; strcpy(e[0].name,"Ajay"); e[0].hr=14; e[0].rate=100; e[0].calculate_gp(); for(i=1;i<3;i++) { cout << "Enter Name of Employee : "<<i+1<<endl;; cin >> e[i].name; cout << "Enter the number of hours worked : "<<endl; cin >> e[i].hr; cout << "Enter the payrate : "<<endl; cin >> e[i].rate; e[i].calculate_gp(); } cout<<"The information about employees"<<endl; for(i=0;i<3;i++) { cout<<"Employee "<<i+1<<endl; cout<<"Name: "<<e[i].name<<endl; cout<<"Hours worked: "<<e[i].hr<<endl; cout<<"Pay Rate: "<<e[i].rate<<endl; cout<<"Gross pay :"<<e[i].gp<<endl; } if((strcmp(e[0].name,e[1].name))==0) { cout<<" Name of employee 1 and employee 2 are same "<<endl; f++; } if((strcmp(e[1].name,e[2].name))==0) { cout<<" Name of employee 2 and employee 3 are same "<<endl; f++; } if((strcmp(e[0].name,e[2].name))==0) { cout<<" Name of employee 1 and employee 3 are same "<<endl; f++; } if(f==0) { cout<<"None of the employee has the same name "<<endl; } return 0;}We will get the following output by compiling the program

Answered: C++ In this exercise, we learning the concept of abstract data type (ADT). Create a structure. Name it Employee. In the Employee structure, keep 3 information…

Database System Concepts

7th Edition

ISBN: 9780078022159

Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher: McGraw-Hill Education

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Question

C++

In this exercise, we learning the concept of abstract data type (ADT).

Create a structure. Name it Employee.
In the Employee structure, keep 3 information about the employee. His/her name (string), numbers of hour worked (int), and his/her pay rate (float).
Inside the main function create an array of struct Employee, keep the size of the array 3 to keep the simplicity of the program.
As a first employee, assign your information.
For second and third employee, ask all the information from the user.
Then display all the information of these three employees with a calculated gross pay.
Then compare the name of all three employees and show if their names are same.
If none of the name is same, must show then don’t have any employees with the same name.

I am adding 3 sample output for better understanding. Feel free to design your output in your way.

Note: Don’t create separate data for all the employee. You must create struct Employee. Don't forget the command cin.ignore().

Sample Output:

see attached images