totoae 1 fg2The mass of the block that can be attached at point E so that the angle indicated (excel) is adequate for member BE. The shorter side of the angle is bolted. Find the weight for ASD, C5.8 m3.2 m1hi123,5 m%3Dh24.5 mh2L203X152X25.4ShapeSteelA992 Gr. 50Gage of Angles75 mmg1T75 mmg2Bolth28mmBolt Diameter, dbolt50 mmAaspace65 mmb,paced.90 mmСэрасе70 mm12dapace90 mmespace95 mmfapaceI || |||

First calculate the strength of member and then find force in member BE according to weight W and…

C hi 3.2 m 5.8 m %3D hz 4.5 m 12 3.5 m h Shape Steel L203X152X25.4 %3D A992 Gr. 50 !! D Gage of Angles gi 75 mm T+ 75 mm g2 Bolt %3! Bolt Diameter, doolt tito 28 %3D mm b A aspace 50 mm %3D b.pace 65 mm 3. Срасе 90 mm 12 dipace 70 mm %3D espace %3D 90 mm fipace 95 mm

C hi 3.2 m 5.8 m %3D hz 4.5 m 12 3.5 m h Shape Steel L203X152X25.4 %3D A992 Gr. 50 !! D Gage of Angles gi 75 mm T+ 75 mm g2 Bolt %3! Bolt Diameter, doolt tito 28 %3D mm b A aspace 50 mm %3D b.pace 65 mm 3. Срасе 90 mm 12 dipace 70 mm %3D espace %3D 90 mm fipace 95 mm

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

British Gravitational Bg System Of Units

Measuring is the comparison of a particular physical quantity with its reference value. A unit is a fixed physical quantity. The length is a physical quantity. A physical quantity is the product of a unit and the numerical value we need to compare with. 

Question

to
to
a
e 1 f
g2
The mass of the block that can be attached at point E so that the angle indicated (excel) is adequate for member BE. The shorter side of the angle is bolted. Find the weight for ASD,

C
5.8 m
3.2 m
1
hi
12
3,5 m
%3D
h2
4.5 m
h2
L203X152X25.4
Shape
Steel
A992 Gr. 50
Gage of Angles
75 mm
g1
T
75 mm
g2
Bolt
h
28
mm
Bolt Diameter, dbolt
50 mm
A
aspace
65 mm
b,pace
d.
90 mm
Сэрасе
70 mm
12
dapace
90 mm
espace
95 mm
fapace
I || |||

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