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C C \CD AB CD AB 00 01 11 10 00 01 11 10 m3 00 1 1 00 1 1 m4 01 1 01 1 1 В B m13 m15 m12 m13 11 X X X X 11 X X X A A mg mg 10 1 X 10 1 D 2 = D' y = CD + C'D' C \CD AB \CD 00 01 11 10 AB 00 01 11 10 m2 0 1 1 00 m7 01 1 01 1 1 1 - B B "15 X 13 "15 m14 m13 11 X X X X 11 X X A A m10 mg "11 "10 10 1 X 10 1 1 X D D x = B'C + B'D + BC'D' w = A + BC+ BD

C C \CD AB CD AB 00 01 11 10 00 01 11 10 m3 00 1 1 00 1 1 m4 01 1 01 1 1 В B m13 m15 m12 m13 11 X X X X 11 X X X A A mg mg 10 1 X 10 1 D 2 = D' y = CD + C'D' C \CD AB \CD 00 01 11 10 AB 00 01 11 10 m2 0 1 1 00 m7 01 1 01 1 1 1 - B B "15 X 13 "15 m14 m13 11 X X X X 11 X X A A m10 mg "11 "10 10 1 X 10 1 1 X D D x = B'C + B'D + BC'D' w = A + BC+ BD

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Write a dataflow description of the BCD-to-excess-3 converter using the Boolean expressions listed in Fig. 4.3 .

C C \CD AB CD AB 00 01 11 10 00 01 11 10 m3 00 1 1 00 1 1 m4 01 1 01 1 1 В B m13 m15 m12 m13 11 X X X X 11 X X X A A mg mg 10 1 X 10 1 D 2 = D' y = CD + C'D' C \CD AB \CD 00 01 11 10 AB 00 01 11 10 m2 0 1 1 00 m7 01 1 01 1 1 1 - B B "15 X 13 "15 m14 m13 11 X X X X 11 X X A A m10 mg "11 "10 10 1 X 10 1 1 X D D x = B'C + B'D + BC'D' w = A + BC+ BD
Transcribed Image Text:C C \CD AB CD AB 00 01 11 10 00 01 11 10 m3 00 1 1 00 1 1 m4 01 1 01 1 1 В B m13 m15 m12 m13 11 X X X X 11 X X X A A mg mg 10 1 X 10 1 D 2 = D' y = CD + C'D' C \CD AB \CD 00 01 11 10 AB 00 01 11 10 m2 0 1 1 00 m7 01 1 01 1 1 1 - B B "15 X 13 "15 m14 m13 11 X X X X 11 X X A A m10 mg "11 "10 10 1 X 10 1 1 X D D x = B'C + B'D + BC'D' w = A + BC+ BD
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