Please help with part c. The first picture has all of the data. (b) Is it plausible that the given sample observations were selected from a normal distribution?O YesO No(c) Calculate a two-sided 95% confidence interval for true average degree of polymerization. (Round your answers to two decimal places.)431.05,444.95Does the interval suggest that 437 is a plausible value for true average degree of polymerization?O YesO NoDoes the interval suggest that 453 is a plausible value?O YesO No An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:416 420 422 423 426 427 430 434 436439 445 446 449 452 454 462 465(a) Construct a boxplot of the data.420430440450460420430440450460420430440450460420430440450Comment on any interesting features. (Select all that apply.)

Given: Degree of polymerization.using the excel formula "=AVERAGE(A2:A18)" sample mean =438 using the excel formula "=STDEV.S(A2:A18)" sample standard deviation s= 15.062 95% confidence interval using the excel formula "=T.INV.2T(0.05,16)" t-value=2.12 CI=x¯±tsn=438±2.1215.06217=438±7.74=(430.26,445.74) Two-sided 95% confidence interval for true average degree of polymerization is (430.26,445.74)

Answered: (c) Calculate a two-sided 95%…

Math

Statistics

(c) Calculate a two-sided 95% confidence interval for true average degree of polymerization. (Round your answers to two decimal places.) 431.05 |× ,444.95

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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