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By using the partial fractions, we have s +6 1 Is(s – 3) Select one: O -2+3e3t O 2- 3et O -3+ 2e3t O 3- 2est O None of the others

By using the partial fractions, we have s +6 1 Is(s – 3) Select one: O -2+3e3t O 2- 3et O -3+ 2e3t O 3- 2est O None of the others

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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By using the partial fractions, we have s +6 1 Is(s – 3) Select one: O -2+3e3t O 2- 3et O -3+ 2e3t O 3- 2est O None of the others
Transcribed Image Text:By using the partial fractions, we have s +6 1 Is(s – 3) Select one: O -2+3e3t O 2- 3et O -3+ 2e3t O 3- 2est O None of the others
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