By use of vector notation, determine the velocity of mass C, and the angular velocity of bar BC when Ɵ=30°.

Fluid A is H20 (Ph20= 62.1 lbm/ft^3) while fluid B is mercury (Phg= 0.488 lbm/in^3), compute the height z if the pressure at x is 5.4 psi vacuum, the distance y= (4-0.5 z) ft and local acceleration of gravity is standard.

PROBLEM S5.3 A thin spherical vessel 1 m in diameter and 12 mm thick is filled with water. More water is pumped in until the pressure reaches 4 MPla. How much extra water is required to reach this pressure? (E = 205 GPa; v = 0.25; K = 2 GPa) [Ans. 1.526 x10-3 m³] Pause Brea Lock Pg Up Num Lock Home Insert

Water flows through a 125 mm diameter pipe at a velocity of 7.5 m/sec. Find the mass flow rate in kg/sec. NOTE: Do not write any unit to your answer, put your answer in a numerical form only and use up to 3 decimal places. ASAP PLS

calculate the pressure in the tank. Please solve it fast within 10-20 Minutes (Answer is P_(tank)= 107kPa , Please don't copy-paste other solution)

9. If the blood viscosity is 2.7x10-3 Pa.s, length of the blood vessel is 1 m, radius of the blood vessel is 1 mm, calculate the tubular resistance of the blood vessel (in GPa.S/m3 ). If the blood pressure at the inlet of the above vessel is 43 mm Hg and if the blood pressure at the outlet of the above vessel is 38 mm Hg. Calculate the flow rate (in ml/min).

At t = 0 the tank shown in fig. is full up to top level, write the differential equation for the function of depth with respect to time. Tank 2 m 2 m conical 1 m 1 m cylinder r = 0.05 m Choose T or F F Case 1: y> 1 case 2: y< 1 m boundary condition at t=tm ,y=1 TI(1)2 dy/dt =0 -cd* t *( 0.05)2 * (2gy)1/2 I(y+1)2 dy/dt =o - cd* n *( 0.05)2 * (2gy)1/2

Oil (s = 0.80) is the fluid in the pipe shown below and mercury (s = 13.6) is the fluid in the manometer. If the deflection Ah is 70 cm and l is 170 cm, what is the gage pressure at the center of the pipe? Flow Ah 2 - Ym{manometer liquid) 4.

- Find V for this mushroom cap on a pipeline. 45° 2 m r 18 m r 3 m3/s – 1 m d V

i am a little lost on how you are changing units    velocity is 2 m/s.    you change it to kg/s   and then m^3/s   i am not seeing the relationship