By the alternating series test, the series First find the partial fraction decomposition of 7 k(k+10) Then find the limit of the partial sums. 8 7(-1) ²+1 k(k+10) k=1 Enter your answer for the sum as a reduced fraction. = 7(-1) k(k+ 10) k=1 7 k(k+10) = converges. Find its sum.
By the alternating series test, the series First find the partial fraction decomposition of 7 k(k+10) Then find the limit of the partial sums. 8 7(-1) ²+1 k(k+10) k=1 Enter your answer for the sum as a reduced fraction. = 7(-1) k(k+ 10) k=1 7 k(k+10) = converges. Find its sum.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
Problem 26RE
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![Textbook
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By the alternating series test, the series
k+1
7(-1) +
k(k + 10)
k=1
7
k(k + 10)
∞
First find the partial fraction decomposition of
7
k(k+10)
Then find the limit of the partial sums.
7(-1) +1
k(k+10)
Enter your answer for the sum as a reduced fraction.
converges. Find its sum.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F71c0ef9f-cd3d-4be0-91e6-4ca83044b87b%2F3450d8d4-25de-4adf-9de5-4853f3c176c4%2Fjq9fl0n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Textbook
Videos [+]
By the alternating series test, the series
k+1
7(-1) +
k(k + 10)
k=1
7
k(k + 10)
∞
First find the partial fraction decomposition of
7
k(k+10)
Then find the limit of the partial sums.
7(-1) +1
k(k+10)
Enter your answer for the sum as a reduced fraction.
converges. Find its sum.
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