By superposition we can express the clectric field produced by multiple charges by addition. A charge qı = 6 µC sits at (1 cm, 1 cm, 0), and another charge q2 at (0, 0, 4 cm). What is q2 that makes Ë at (0, 2 cm, 0) with zero y-component? %3D
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- Positive charge is distributed in a sphere of radius R that is centered at the origin. Inside the sphere, the electric field is Ē(r) = kr-1/4 f, where k is a positive constant. There is no charge outside the sphere. a) How is the charge distributed inside the sphere? In particular, find an equation for the charge density, p. b) Determine the electric field, E(r), for r > R (outside the sphere). c) What is the potential difference between the center of the sphere (r = 0) and the surface of the sphere (r = R)? d) What is the energy stored in this electric charge configuration?A line of charge of length L = 42 cm with charge Q = 430.0 nAies along the positive Y axis whose one end is at the origin O. A point charge q = 310.0 µClies on point P = (41, 21.0)Here the coordinates are given in centi-meters. a) Find the Electric field at Pdue to the rod. x component of E Give your answer to at least three significance digits. N/C y component of E Give your answer to at least three significance digits. N/C b)Find the charge density of the rod? why is it in C/mbut not in C/m?? Charge density Give your answer to at least three significance digits. C/m1 ! 7 A skát с A spherically symmetric charge distribution produces the electric field E=( 5400 r²) N/C, where r is in m. Z mylabmastering.pearson.com/?courseld=12649908&key=55673220682936520262024#/ 2 pos W S X 3 20 F3 E D $ 4 C 888 R F What is the electric field strength at r= 16.0 cm ? Express your answer in newtons per coulomb. VG ΑΣΦ 4 Submit Part B Submit Part C What is the electric flux through a 32.0-cm-diameter spherical surface that is concentric with the charge distribution? Express your answer in newton meters squared per coulomb. ΕΠΙ ΑΣΦ % [VG| ΑΣΦ 5 Request Answer V FO Request Answer T How much charge is inside this 32.0-cm-diameter spherical surface? Express your answer in coulombs. G 4 a ^ 6 C 244 MacBook Air Y B SMC & ? 7 H ? N/C 80 F7 N-m²/C U C N H 8 - DII FS 1 ( 9 M DD K chegg.com X C ☆ O O MOSISO O 4 P
- A non-uniformly charged insulating sphere has a volume charge density p that is expressed as p= Br where B is a constant, and r is the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for B? Sol. By definition, the volume charge density is expressed infinitesimally as p= where in is the infinitesimal charge and is the infinitesimal volume. so, we have P = dq/ = B so we can write this as dq = B dV But, dV = dr By substitution, we get the following dq = 4B dr Using Integration operation and evaluating its limits, the equation, leads to Q = Rearranging, we get B = 4)A non-uniformly charged insulating sphere has a volume charge density p that is expressed as p= Br where B is a constant, and r is the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for B? Sol. By definition, the volume charge density is expressed infinitesimally as p= where in is the infinitesimal charge and is the infinitesimal volume. So, we haye p = dq/ So we can write this as dq = B dV But, dV = dr By substitution, we get the following dq = 4BT dr Using Integration operation and evaluating its limits, the equation, leads to Q = BT Rearranging, we get B = /( TA non-uniformly charged insulating sphere has a volume charge density p that is expressed as p= Br where B is a constant, and r is the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for B? Sol. By definition, the volume charge density is expressed infinitesimally as p= where in is the infinitesimal charge and is the infinitesimal volume. so, we have p = dq/ So we can write this as dq = B dV %3D But, dV = dr
- solvEx. Consider a negative charge –Q that is uniformly distributed along the yaxis between y =0 and y = l as shown. Which of the following is the correct expression for the a-component of the net electric field at point P? +y Q P + x ydy (2 + y?)3/2 OA. kQ O B. kQ ydy (교2 + y?)s/2 zdy kQ ( + y )3/2 OC. OD. kQ zdy (22 + y?)3/2Positive charge Q is distributed uniformly along the positive y-axis between y=0 and y=a. A negative point charge −q lies on the positive x-axis, a distance x from the origin Calculate the x-component of the electric field produced by the charge distribution Q at points on the positive x-axis. Express your answer in terms of the variables Q, x, y, a and appropriate constants. Calculate the y-component of the electric field produced by the charge distribution Q at points on the positive x-axis. Express your answer in terms of the variables Q, x, y, a and appropriate constants. Calculate the x-component of the force that the charge distribution Q exerts on q. Express your answer in terms of the variables Q, q, x, y, a and appropriate constants. Calculate the y-component of the force that the charge distribution Q exerts on q. Express your answer in terms of the variables Q, q, x, y, a and appropriate constants.= Three uniform charge distributions are present in a region: an infinite sheet of charge, a finite line charge, and a ring of charge. The infinite sheet of charge at (x, -3, z), where x and z spans from negative to positive infinity, has a charge density Ps 5 nC/m². The finite line charge at (0, -1, z), where z ranges from -2 to 2, has a charge density -4 nC/m. Finally, the ring of charge, with a radius of 3m and charge density PL 2 nC/m, is parallel to the xz-plane centered at (0, 4, 0). All coordinates are in meters. Use the value k = 9 x 10⁹ in your solutions and = answers. Question: Determine the magnitude the electric field due to the infinite sheet charge only at (0, 2, 0).
- Here’s one more model of an electron. Here e is the magnitude of the charge of an electron, and R is a constant parameter characterizing the electron’s size: rho=-e (105/4pi)r2(R-r)2/R7 , rho = 0 for r >R. a. Use the problem's symmetry to evaluate the electric field at all points in space, it r >R and r<R. b. Sketch the electric field magnitude versus r for all values of r. d. evaluate the electric potential at all points in space and sketch its magnitude as a function of r.Negative charge -Q is distributed uniformly around a quarter-circle of radius a that lies in the first quadrant, with the center of curvature at the origin. Part A: Find the x-component of the net electric field at the origin. Part B: Find the y-component of the net electric field at the origin. Express your answer in terms of the variables Q , a and appropriate constants.Half ring uniformly charged with charge Q is placed on the 2nd and 3rd quadrant like you see in the picture. The radius is R. The linear charge density is A. What is the correct equation to find the x component of the electric field at the origin?