The equation x - 16x³ = 0 O (A) has two (and only two) distinct real roots O (B) has four (and only four) distinct real roots O (C) has nine distinct real roots O (D) has three (and only three) distinct real roots O(E) cannot be solved

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The equation x - 16x = 0
O (A) has two (and only two) distinct real roots
O(B) has four (and only four) distinct real roots
O (C) has nine distinct real roots
O (D) has three (and only three) distinct real roots
O (E) cannot be solved
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Transcribed Image Text:8 answered ed out of 00 Flag question The equation x - 16x = 0 O (A) has two (and only two) distinct real roots O(B) has four (and only four) distinct real roots O (C) has nine distinct real roots O (D) has three (and only three) distinct real roots O (E) cannot be solved Previous Next
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Follow-up Question

yes but the negative radical 2 is not a real number and in the options they are asking for a real distinct solution

3:38
Solutions Solving Steps
The expressionIS UNTUTTined in the set oricar
numbers
Simplify
Undefined
0=0
0=0
x#-√3
0=0
0=0
Since the expression is undefined in the
set of real numbers, x= -√3 is not a
solution of the equation
x= -√3
x=0
x = √3
The equation has 2 solutions
Solution
x₁ = 0₁x₂ = √3
0,
Alt
ive Form
.4G
Next Step
5
X₁−u, X₂~1,73200
X
Transcribed Image Text:3:38 Solutions Solving Steps The expressionIS UNTUTTined in the set oricar numbers Simplify Undefined 0=0 0=0 x#-√3 0=0 0=0 Since the expression is undefined in the set of real numbers, x= -√3 is not a solution of the equation x= -√3 x=0 x = √3 The equation has 2 solutions Solution x₁ = 0₁x₂ = √3 0, Alt ive Form .4G Next Step 5 X₁−u, X₂~1,73200 X
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Follow-up Question

yes i understand how to solve it and i know we get 3 values but dont you automatically reject the negative because the exponents are fractions?

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Follow-up Question

but isnt it 2 distinct roots?

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