A 5μF capacitor with air between the metal plates is connected to a 12V battery. The battery is then removed, leaving the capacitor charged. (a) Calculate the charge on the capacitor. (b) The air between the plates is replaced by oil with er = 3. Find the new value of capacitances and the new potential difference between the plates.
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An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
A 5μF capacitor with air between the metal plates is connected to a 12V battery. The battery is then
removed, leaving the capacitor charged.
(a) Calculate the charge on the capacitor.
(b) The air between the plates is replaced by oil with er = 3. Find the new value of capacitances and the new potential difference between the plates.
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But I found this equation for non-vacuum between the plate, I no need to deduct the Er of air 1.005?
Please see attachment.
In part (b), do I need to take over the relative permittivity of AIR, that mean
C new = 3*5μF/1.0006 ?