Buffering Capacity pH vs. Volume of Base 12 y 0.0004x3-0.0238x2+ 0.4761x+ 7.797 R2 1 y 0.0005x0.0211x +7.314 Group 1 10 R 1 Group 2 8 y=9E - 06x 2 + 0.0055x+ 7.2604 R2 1 Group 3 O 6 Log. (Group 3) Power (Group 3) 4 Poly. (Group 3) 0 0 50 100 150 200 250 300 Volume of Base

4. What is the pH of the buffer that results when 5.00 mol of H SO, and 2.00 mol of CalOH), are diluted with 1.00 Lof water. K, of H,SO,- 1.2x 10 ) Reaction Equation: pH:

[Review Topics] [References] Use the References to access important values if needed for this question. A buffer solution that is 0.438 M in CH3COOH and 0.438 M in CH3COOK has a pH of 4.74. Addition of which of the following would increase the capacity of the buffer for added OH? (Select all that apply.) pure water both CH3COOH and CH3COOK simultaneously CH3COOH CH3COOK none of the above Submit Answer Retry Entire Group 3 more group attempts remaining

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M of NaOH: 0.100 Volume  of HCI 25mL = 0.025L Moles of HCI = 2.5 mol What is the Volume of  NaOH  equivalence point: What is  Moles of NaOH  equaivalence point: What  is pH at equivalence point? What is calculated pH and experimental pH of NaOH at 0.00 mL , 12.50 mL, 25mL, and 30 mL. Also what is the Error percentage for each one?

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