Answered: break the system y'1 = 4y1 + y3 y'2 =…

break the system y'1 = 4y1 + y3 y'2 = -2y1 + y2 y'3 = -2y1 + y3 and search solving conditions that meet the initial conditions y1(0) = -1 y2 (0) = 1 y3 (0) = 0

Linear Algebra: A Modern Introduction

4th Edition

ISBN:9781285463247

Author:David Poole

Publisher:David Poole

Chapter2: Systems Of Linear Equations

Section2.4: Applications

Problem 15EQ

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Question

break the system

y'₁= 4y₁+ y₃

y'₂= -2y₁+ y₂

y'₃= -2y_{1 +}y₃

and search solving conditions that meet the initial conditions

y₁(0) = -1

y₂(0) = 1

y₃(0) = 0

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