
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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bond order of O2 minus
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- Draw a Lewis structure for a compound with a bond order of 2 throughout the molecule.arrow_forwardMolecule or Polyatomic HOCI NO₂ N₂H4 H₂O₂ Hint: the oxygens are connected (CH3)2NH Lewis structure H¬O—CI: | : 0=N–6: H-N-N-H H H H-0-0-H H H H-C-N -C-H .. HHH Hybrid- ization AXE 3 sp AX₂E2 2 sp² AX₂E 3 sp³ AX3E 3 sp AX₂E2 3 AX3E Electron pair geometry Molecular shape tetrahedral bent trigonal planar bent tetrahedral trigonal pyramidal tetrahedral bent tetrahedral trigonal pyramidal Bond angles ~109.5° ~109.5° all ~109.5° all ~109.5° all ~109.5° Bond Polarity Molecular Polarity if the molecule is polar, add a dipole arrow if not polar, state so and why H H H²O-OH Н H H" H H H Н Cl H 'H Harrow_forwardI. Put these in order of increasing bond length. C=C C-C C=C II. Put these in order of of increasing bond order. Is there a connection between bond order and bond length?arrow_forward
- The overlap of atomic orbitals shown here will give rise to a molecular orbital with what type of character? P. O bonding character O* anti-bonding character non-bonding character O bonding character T* anti-bonding character T bonding character 8* bonding characterarrow_forwardHow many unpaired electrons doe the molecule Liz have? What's the bond order of the diatomic molecule Li2? Is Liz a stable species? Is it paramagnetic or diamagnetic? 2 unpaired electrons; bond order 1; stable; paramagnetic O 2 unpaired electrons; bond order 1; stable; diamagnetic O unpaired electrons; bond order 1; stable; paramagnetic O unpaired electrons; bond order 1; stable; diamagneticarrow_forwardComplete the following table: Lewis structure atoms: bonds between orbitals making each total bond order hybridization atoms: type E valence bond: between two atoms |Н: 1s C and H: o sp?(C) + 1s(H) C and H: 1 C: sp? Cl: sp3 0: sp? :0: || C and Cl: o sp?(C) + sp°(CI) C and Cl: 1 = sp?(C) + sp²(0) = p(C) + p(0) C and O: o C and O: 2 CI C and O: t C: C and C: C and C: C and C: C: H-C=C-H H: C and H: C and C: H: C and H: N: N and I: N and I: N= I: N and I: C: C and Cl: C and Cl: :Cl Cl: C and Cl: C and Cl: Cl: C and Cl: -c=cl: C and Cl: :Z: :U:arrow_forward
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