Body Mass Index: In a survey of adults with diabetes, the average body mass index (BMI) in a sample of 1924 women was 31.10 with a standard deviation of 0.4. The BMI in a sample of 1555 men was 30.30 , with a standard deviation of 0.7. Part: 0/ 2 Part 1 of 2 (a) Construct a 95% confidence interval for the difference in the mean BMI between women and men with diabetes. Let u, denote the mean BMI for women with diabetes. Use the TI-84 calculator and round the answers to two decimal places. A 95% confidence interval for the difference in the mean BMI between women and men with diabetes is

The mean score on a driving exam for a group of driver’s education students is 76 points, with a standard deviation of 6 points. Apply chebychev’s theorem to the data using K=2. Interpret, At least ___% of the exam score falls between ___and ____

1) Which is relatively better: a score of 88 on a Psychology test or a score of 45 on an Economics test? Scores on the Psychology test have a mean of 92 and a standard deviation of 10. Scores on the Economics test have a mean of 57 and a standard deviation of 5. Use measures of relative position to answer this exercise (Z-score).

Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of women

In a school district, all sixth grade students take the same standardized test. The superintendant of the school district takes a random sample of 3030 scores from all of the students who took the test. She sees that the mean score is 169169 with a standard deviation of 7.06747.0674. The superintendant wants to know if the standard deviation has changed this year. Previously, the population standard deviation was 1313. Is there evidence that the standard deviation of test scores has decreased at the α=0.005α=0.005 level? Assume the population is normally distributed. Step 1 of 5:  State the null and alternative hypotheses. Round to four decimal places when necessary. Step 2 of 5:  Determine the critical value(s) of the test statistic. If the test is two-tailed, separate the values with a comma. Round your answer to three decimal places.     Step 3 of 5:  Determine the value of the test statistic. Round your answer to three decimal places. Step 4 of 5:  Make the…

Calcium is essential to tree growth. In​ 1990, the concentration of calcium in precipitation in a certain area was 0.11milligrams per liter (mg/L).A random sample of 10 precipitation dates in 2018 results in the following data table. Complete parts​ (a) through​ (c) below. (B) With 98​% confidence, the mean concentration of calcium in precipitation in this area in 2018 is between