Block A weighs 10.5 lb and block B weighs 6.5 lb. The static friction coefficient between blocks A & B is 0.32. The static friction coefficient between blocks B and the inclined surface is 0.37. If the incline is ? = 30∘ what is the smallest force P required for motion?

The crate pulled by a man as shown weighs 200 N. Supposed that the static friction coefficient between the contact surfaces is 0.25. Determine the following: a.) The value of angle alpha (ᾳ) to obtain the smallest possible value of the pulling force the man exerted so that the crate is on the verge of moving. b.) The smallest value of the pulling force the man exerted, c.) The normal reaction between the contact surfaces (Crate and Horizontal floor).

please answer do not image format

draw free body diagram and A and B please. picture is pretty clear! Block is labeled A (under A is 25 degrees) above is 45 degrees and F pulling down is 50 degrees

Help!!! Answer it correctly!!! Make sure you solve work on hand!!! Answer correctly Please!!!!!!!

Question 5 If the coefficient of static friction at contact points A and B is 0.46 calculate the maximum force P that can be used without causing the 196 kg spool to move. (X,XX,XXX represents the last digits number pf your IC) 0.6 m 0.9m

8. Answer the following questions about the exercise of Box A (massmA=50kg) and Box B (mB=10kg) located on the slope as shown in Figure 7. Between slope and box A, the coefficient of static friction is uk, and the angle of slope is 10 degrees, although box A and B are connected in a solid line and ignore the mass of the pulley.1)What is the maximum friction (kgf) between Box A and Slope for us=0.4 and Uk=0.15?2)What is the maximum friction between Box A and the slope (kgf) for us=0.3 and UK=0.15?3)us=0.3 and Uk=0.15 What is the tension in kgf?4)us=0.3 and uk=0.15 when box B goes down 2m, calculate the size (m/s) of the speed of box A and box B using the modified energy supply law.

Please asap

A 250-lb block rests on a horizontal surface, as shown. The coefficient of static friction is 0.25. Calculate the maximum value of the horizontal force P so that neither sliding nor tipping will occur. 2'-0" W = 250 lb P. 4' 6" 3'-0"