Block A is held in equilibrium when force F = 100 lbf is applied. Each cable is made out of 6-0s gage B & S Non Ferrous Metals wire. Determine the normal stress in each cable and the mass of block A. You may assume the cables and pulleys have negligible mass. AB= number (rtol=0.01, atol=1e-05) OBC= number (rtol=0.01, atol=1e-05) OCD= number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) ODE B mA = (C A D ksi ksi E ksi ksi slugs F

Block A is held in equilibrium when force F = 100 lbf is applied. Each cable is made out of 6-0s gage B & S Non Ferrous Metals wire. Determine the normal stress in each cable and the mass of block A. You may assume the cables and pulleys have negligible mass. AB= number (rtol=0.01, atol=1e-05) OBC= number (rtol=0.01, atol=1e-05) OCD= number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) ODE B mA = (C A D ksi ksi E ksi ksi slugs F

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

please help answer and explain

Block A is held in equilibrium when force F = 100 lbf is applied. Each cable is made out of 6-0s gage B & S
Non Ferrous Metals wire. Determine the normal stress in each cable and the mass of block A. You may
assume the cables and pulleys have negligible mass.
JAB =
JBC =
OCD =
ODE=
mA =
B
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
number (rtol-0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
(C
A
D
ksi
ksi
ksi
ksi
(E
?
slugs ?
F

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