Bipti is a chemist at VenkatanarasimharajuvaripetaChemical Ltd. She has published her results of the isomers of 2-Fluoropropane . The resultant masses of the isomers chosen are as follow: 5.6 gr, 5.1 gr, 4.6gr, 4.8 gr, 5.7 gr and 6.4 gr. Construct a 90 % confidence level for these sample data.

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 132 millimeters, and a variance of 64. If a random sample of 39 steel bolts is selected, what is the probability that the sample mean would be greater than 128.2 millimeters? Round your answer to four decimal places. Answer How to enter your answer (opens in new window) Keypad Keyboard Shortcuts Tables

Please answer the incorrect ones only.

One method for measuring air pollution is to measure the concentration of carbon monoxide, or CO, in the air. Suppose Nina, an environmental scientist, wishes to estimate the CO concentration in Zagreb, Croatia. She randomly selects 45 locations throughout the city measures the CO concentration at each location. Based on her 45 samples, she computes the margin of error for a 95% t-confidence interval for the mean concentration of CO in Zagreb, in µg/m³, to be 4.28. What would happen to the margin of error if Nina decreases the confidence level to 90%? Nina increases the confidence level to 99%? Nina decreases the sample size to 33 locations? Nina increases the sample size to 65 locations? Answer Bank Increase Stay the same Decrease

The accompanying data are the weights (kg) of poplar trees that were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Also shown are partial results from using the Bonferroni test with the sample data. Complete parts (a) through (c). c. Use the Bonferroni test procedure with a 0.10 significance level to test for a significant difference between the mean amount of the irrigation treatment group and the group treated with both fertilizer and irrigation. Identify the test statistic and the P-value. What do the results indicate? The test statistic is (Round to two decimal places as needed.) Find the P-value. P-value (Round to three decimal places as needed.) = No Treatment 1.26 0.42 0.66 0.09 1.23 (1) TREATMENT 1.00 Fertilizer 0.81 0.79 0.44 0.61 1.06 Irrigation 0.09 0.53 0.11 0.82 0.83 Bonferroni Results Mean (J) TREATMENT Difference (I-J) 2.00 3.00 4.00 -0.0100 0.2560 -0.9140 Fertilizer and Irrigation…