
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Why don't we use Eq. 2 as the operative equation for this lab, instead of Eq. 3?

Transcribed Image Text:between the negatively charged electron and the positively
charged nucleus. The contrast in length scales between planetary
orbits, with radii on the order of 102 m, and atomic orbits, with
radii on the order of 1010 m, is worthy of note. On more
moderate length scales, in human affairs, tire friction provides
the centripetal force which moves a car in a circular path. And
an object swung around overhead (for example, a lasso) does so
in response to the centripetal force provided by the tension in the
rope.
Substituting the expression for centripetal acceleration,
1.
derived in your textbook, into Newton's second law, F-ma, one
finds an expression for the centripetal force:
my
F.
The mass, m, and the radius of motion, r, are each directly
measurable quantities. After measuring the object's period T (the
time required for one complete revolution) the velocity can be
determined from the relation v= di = 2/T. Substituting this
expression for v into the expression for Fe gives
F.
In this lab, a spring's tension provides the centripetal force. You
will measure m, r, and T, and use Eq. (3) to find Fe from them.
Since the spring's tension is a function of the length to which it is
stretched, you can compare Fe as calculated above, with a more
direct measurement of the same force. Draping a string over the
pulley, the hanging mass that stretches the spring to the same
length that the rotating bob did must have a weight equal to Fo
The comparison between the directly measured force (the weight
used in the static approach) and the value of Fe found from Eq. 3
will be the bottom line in your calculations.
33

Transcribed Image Text:Procedure
J1. Weigh your object and record its mass on the data sheet under Trial 1
Mass.
v2. For your first trial, set the vertical "marker rod" as close as possible to
the axis of rotation. When set into circular motion, the bottom point of
the object should pass directly over the marker rod.
3. Measure the distance from the center of the marker rod to the center
of the axis of rotation, and record this on the data sheet under Trial 1
Radius.
4. Adjust the horizontal boom so that the strings from which the object
hangs will lie in a vertical plane. Tighten both the marker rod and the
boom in place. Note that the strings upward tension will then cancel the
downward gravitational force on the object. Also balance the apparatus
by adjusting the counterweight so that the whole system rotates
smoothly.
6. Reattach the spring and turm the rotor just fast enough so that the bob
passes directly over the marker rod. After some practice at giving the
mass a reasonably uniform speed, you will find that you are pushing a
tiny amount each revolution in order to compensate for frictional losses.
As always, practice and patience are your keys to good honest data.
7. Determine the period T(the time for each revolution) by dividing the
time for 20 revolutions by 20. Record this on the data sheet under
Trial 1 Period.
8. Use your experimental values of m r, and Tin Eq. (3) to calculate the
centripetal force, and enter this value in the appropriate box on the data
sheet. Show your work in the space provided on the data sheet.
9. Directly measure the spring's force by stretching it to the same
extension it had when rotating. Do this by attaching some hanging
masses on a string draped over the premounted pulley, which is used
merely to redirect the downward force of gravity. If the spring is
stretched to the same length as when it was spinning, the weight of the
hanging masses (mg) should equal the centripetal force to within
experimental error. Record this on the data sheet under Trial 1 Directly
Measured Force.
10. Reset the marker rod to the largest radius of its range, and repeat
steps 1 through 9 two more times, for your second trial.
11. For the third trial add a 100 g flat weight on top of the mass, and
leave the radius unchanged from that of trial 2.
34
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