Between a plate and the body of a bolt or a pin, the average bearing stress is computed by dividing the transmitted force by the area. A cross-sectional B projected semicircular contact contact

SIMPLE STRESSES 340 mm 3. Two plates are connected by bolts as shown in the figure. Compute the maximum force F that can be applied to the plates. The allowable axial stress of each plate is 150 Mpa. The allowable shear stress of each bolt is 50 MPa. The diameter of each bolt is 16 F F 150 mm mm. 50 mm 340 mm

The rigid beam is supported by a pin at B and wires AD and CE. (Figure 1) The load P on the beam causes the end A to be displaced 7.5 mm downward. The wires are unstretched when the beam is in horizontal position. Figure 3 m 2 m -2 m 1.5 m E 1 of 1 2 m ▼ Part A Determine the normal strain developed in wire CE. Express your answer in millimeters per millimeter to three significant figures. ECE = Submit Part B E AD = Submit D Provide Feedback AEO Ivec Request Answer Determine the normal strain developed in wire AD. Express your answer in millimeters per millimeter to three significant figures. AE Ivec S ? Request Answer mm/mm ? mm/mm

SITUATION. A steel plate ABCD of thickness t = 5mm is subjected to uniform stresses: = 100 MPa 0₂ = -60 MPa. Ox E =200GPa, v= 1/3 a = 160mm and b = 200 mm Calculate the change in thickness (mm). -0.0023 mm 0.0023 mm O O 0.0045 mm - 0.0045 mm Ł B AL C D X

Question: A 12 mm thick plate is connected to two 8 mm thick plates, on either side through a 16 mm diameter power driven field rivet as shown in the figure below. Assuming permissible shear stress as 9- MPa and permissible bearing stress as 270 MPa in the rivet, the rivet value of the joint is P/2 - F 8 mm 8 mm ↓ 12 mm P

Please solve this question and please mention the all the correct answer 

The axial load 396 kN applied to the lap joint is distributed equally among the three 20.6-mm-diameter rivets. What is the maximum tensile stress (in MPa) in the plate if w = 135.4mm and t = 27.1mm? Round off the final answer to three decimal places.

4.c

A solid brass shaft is loaded as shown below by two torques TB= 1100 Nm and TC= 400 Nm. The lengths of the two segments are LAB= 750 mm and LBC= 600 mm. For brass, G = 41 GPa. Neglect the effect of any stress concentrations. Determine the smallest diameters dAB and dBC for which an allowable shear stress of 60 MPa is not exceeded. Express each diameter as an integer in units of mm.

The failure stress of a homogeneous steel bar having a diameter of 10 mm is 250 MPa. Using a factor of safety of 2.0, calculate the maximum load in N that the bar can support. A 12500*pi В) 6250*pi C) 3125*pi 1563*pi