Ben attempts 8 three-point shots. From much past performance, the probability Ben will make a three-point shot is 20%. Let x = the number of three-point shots Ben makes in eight attempts. a) Determine: i) P(x = 2) ii) (x ≤2) b) Determine the probability Ben will make at least one of the eight three-point shots he attempts.

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A: First we will calculate the expected value or E(X).         x=2,3,4,5P(X=x)=0.20, 0.30, 0.20, 0.30…

Q: Given P(A) = 0.40. P(B) = 0.30 and P(A and B) = .10. find (a) P(AU B).(b) P(A | B), and (c) P(B |A),

A: Given,P(A)=0.40P(B)=0.30P(A∩B)=0.10

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Q: Given P(A) = 0.7 and P(B) = 0.8. If P(A/B) = 0.3 find P(A and B).

A: Given that  P(A)=0.7 , P(B)=0.8 P(A/B)=0.3

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A: Given,P(A)=0.40P(B)=0.25P(B/A)=0.11

Q: If P(A or B) = 0.7 and P(A) = 0.44, and P(A and B) = 0.22, determine P(B)

A:

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Q: If P(B) = 0.3, P(A or B)= .06, and P(A and B)= .2, find P(A)

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Q: If P(A) =0.7, P(B) = 0.1 and A and B are mutually exclusive, find  P(A and B)

A: From the provided information, P (A) = 0.7, P (B) = 0.1

Q: (d) At least 13 of them do not use the website.

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Q: Suppose P(A)=0.6, P(B)=0.4, and both A and B are independent. Calculate P(A or B).

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Q: if P(A) = 0.65, P(B) = 0.8, P(AN B) = 0.55 Then, P(B | A) is Select one: a. 55 80 b. 55 65 C. 65 80…

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A: We have given that p(a)= 0.40  p(b) = 0.20  p(b|a)= 0.30 p(a|b) = ?

Q: given that P(A or B) = 1/3, P(A) = 1/7, and P(A and B) = 1/8, find P(B) a. 101/168 b. 159/168 c.…

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Q: Given P(A) = 0.2, P(B) = 0.6 do the following.  If P(A | B) = 0.1, compute P(A and B).

A: Given that  P(A) = 0.2, P(B) = 0.6 P(A | B) = 0.1 Find P(A and B)

Q: P(x ≥ 120); p = 100,σ = 15

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Q: (507)10= ... Select one: a. (377)8 b. (327)s c. (773)8

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Q: Round to the fourth a) Find P(Z<-3.3)=

A: Solution-: We find, P(Z&lt;-3.3)=?