Below is given the FT-IR (Fourier Transform Infra Red) data of a 1:1 (by weight) mixture of ethylene carbonate (EC) and dimethyl carbonate (DMC). Absorbance P is given as a function of wavenumber, m. Regress the above data to a second order polynomial P = a, + a, m + az m² Find the absorbance at m = 1000 cm-1 Wavenumber, m ( cm-1) Absorbance, P (arbitrary unit) 804.184 0.1591 827.326 0.0439 846.611 0.0050 869.753 0.0073 889.038 0.0448 0.0649 892.895 900.609 0.1204
Below is given the FT-IR (Fourier Transform Infra Red) data of a 1:1 (by weight) mixture of ethylene carbonate (EC) and dimethyl carbonate (DMC). Absorbance P is given as a function of wavenumber, m. Regress the above data to a second order polynomial P = a, + a, m + az m² Find the absorbance at m = 1000 cm-1 Wavenumber, m ( cm-1) Absorbance, P (arbitrary unit) 804.184 0.1591 827.326 0.0439 846.611 0.0050 869.753 0.0073 889.038 0.0448 0.0649 892.895 900.609 0.1204
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Q2: Below is given the FT-IR (Fourier Transform Infra Red) data of a 1:1 (by weight) mixture of ethylene carbonate (EC) and dimethyl carbonate (DMC). Absorbance P is given as a function of wavenumber, m. Regress the above data to a second order polynomial P = a, + a, m + az m² Find the absorbance at m = 1000 cm-1 Wavenumber, m ( cm-1) Absorbance, P (arbitrary unit) 804.184 0.1591 827.326 0.0439 846.611 0.0050 869.753 0.0073 889.038 0.0448 0.0649 892.895 900.609 0.1204
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