Below is another motion diagram for an object that moves along a curved path. The dots represent the position of the object at five subsequent instants, t1 t2, t3, t4, and t5. The vectors v21, V32, V43, and v54 represent the average velocity of the object during the four corresponding time intervals. Draw the acceleration vectors a31 and as3 representing the changes in velocity of the object during the time intervals At31 = t3 -t1 and At53 = t5 -t3. respectively. Draw the vectors starting at the appropriate black dots. The location, orientation, and length of the vectors will be graded. Vectors: āsa Acceleration between times 3 and 5 āsi acceleration between times 1 and 3 -vas Vector opposite to v43 -V21 Vector opposite to v21

A cyclist is travelling along a straight road. Graph 1 shows the cyclist's velocity during the first 32 s of his journey. 2. 30.0 25.0 20.0 15.0 10.0 5.0 0.0 0.0 5.0 10.0 15.0 20.0 25.0 30.0 35.0 Time (s) Graph 1 Sketch a graph of position on the vertical axis against time on the horizontal axis for the jourmey. a. b. Determine the average acceleration of the cyclist during: i. The first 16 seconds ii. Between 16 seconds and 24 seconds iii. Between 24 seconds and 32 seconds Calculate the average acceleration of the cyclist for the entire journey. d. Calculate the total distance that the cyclist travelled during the first 24 seconds. e. Draw a motion diagram that corresponds to Graph 1. Velocity (m/s)

A group of students in a science class monitored the movement of a cat walking along with a straight line and recorded the cat's position in five-second intervals.The results are summarized it in the table below.  time and position time(s) position (cm) 0 49.0 5 38.0 10 43.0 15 40.0 20 60.0   A. What is the displacement of the cat between t = 5.00 s and t = 20.0 s?   B. What is the average velocity of the cat between t = 5.00 s and t = 20.0 s?   C.What is the distance the cat traveled between t = 5.00 s and t = 20.0 s?

After a constant acceleration of 3.52 m/s/s at 9.6 degrees above the +x-axis is applied by the motors of a boat for 7.05 seconds, the boat is moving at 96.8 m/s at 34 degrees above the +x-axis. What was the displacement of the boat during this time? What is the angle from the positive x-axis?

Starting at x = - 14 m at time t = 0 s, an object takes 17 s to travel 42 m in the +x direction at a constant velocity. On a sheet of paper, make a position vs. time graph of the object's motion. What is its velocity

An object moves in the x-y plane with a constant acceleration of 2i +3j meters per second squared. The object starts at the origin with some initial velocity. After four seconds (4 seconds) the velocity of the object is 2i + 8j meters per second. Determine the object’s initial velocity. Leave answer in i-j notation. Determine the position of the object at time, t = 4 seconds. Leave answer in i-j notation.   Thank you for your help.

At t=0 an object has a position of 1 m and has a steady velocity of -2.5 m/s.     What will be the object’s position at t = 6 seconds? Make a sketch of position vs. time for this motion from t=0 to t=6 s. Make a sketch of velocity vs. time for this motion from t=0 to t=6 s. Does the object change directions between 0 and 6 s?

The figure shows the acceleration-versus-time graph of a particle moving along the x-axis. Its initial velocity is vox = 6.00 m/s at to = 0 s. What is the particle's velocity at t = 2.00 s? (Figure 1) 1 of 1 Figure a (m/s²) 4 2- 0 2 4 t(s) Part A Express your answer with the appropriate units. μA ? m 14 S Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining Provide Feedback

A ball moves along a 1D coordinate system with the following motion parameters at time t = 0 s: x₁ = 1.9 m and vo = 0 m/s. The ball has a constant acceleration of 1.1 m/s2 during the entire motion which occurs over a time of 1.2 s. Assume that an error in position of 4% is acceptable in this application over the entire motion. How many rows N will be needed in the table to model the entire motion to within the required error even though you are leaving out the final term of 1/2 a (At )²) present in the exact position expression?

A helicopter starts ascending in the sky from the ground and its position is given by 5t2 + 10t. After 10 seconds, a package is dropped out from the helicopter. What is the velocity of the package when it descends to a height of 10 m above the ground. Y =