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I got the first two parts correct but the last I am struggling with my strategy so far is using the intensity=watts/area formula with 8.680e+09 V/m as the intensity of the wattage I found previously and the area I am using the diameter form of the circle equation. then I used algebra to solve. The issue I believe is that 8.680e+09 V/m is not in the right units but am not sure where to progress from there.

**Ultrafast Laser**

One of the highest power lasers in the world is located at the General Research Lab Building at Colorado School of Mines. It emits pulses lasting approximately 24 femtoseconds (fs) and containing 91 millijoules (mJ) of energy. Here, "fs" denotes a femtosecond, which is \(10^{-15}\) seconds.

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**Peak Power**

- **Question:** What is the average power associated with a single pulse?
- **Answer:** \( \text{Power} = 3.792 \times 10^{12} \, \text{J/s} \)

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**Pulse Length**

- **Question:** What is the physical length of this pulse?
- **Answer:** \( \text{PulseLength} = 7.20 \times 10^{-6} \, \text{m} \)

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**Beam Diameter**

When the beam exits the laser, it has a diameter of approximately 30 mm. Molecules start to ionize when applied electric fields reach approximately \( 8.680 \times 10^9 \, \text{V/m} \). The beam must be focused to a diameter of 8285.223 m to reach this electric field strength.
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Transcribed Image Text:**Ultrafast Laser** One of the highest power lasers in the world is located at the General Research Lab Building at Colorado School of Mines. It emits pulses lasting approximately 24 femtoseconds (fs) and containing 91 millijoules (mJ) of energy. Here, "fs" denotes a femtosecond, which is \(10^{-15}\) seconds. --- **Peak Power** - **Question:** What is the average power associated with a single pulse? - **Answer:** \( \text{Power} = 3.792 \times 10^{12} \, \text{J/s} \) --- **Pulse Length** - **Question:** What is the physical length of this pulse? - **Answer:** \( \text{PulseLength} = 7.20 \times 10^{-6} \, \text{m} \) --- **Beam Diameter** When the beam exits the laser, it has a diameter of approximately 30 mm. Molecules start to ionize when applied electric fields reach approximately \( 8.680 \times 10^9 \, \text{V/m} \). The beam must be focused to a diameter of 8285.223 m to reach this electric field strength.
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