Can you solve the question in the pictures shown? battery maintains a potential difference of 12.0 V.(a) If P is connected to the negative terminal, whatis the capacitance of the three-plate system P,P,P3?(b) What is the charge on P,? (c) If P, is now connectedto the positive terminal, what is the capacitance ofthe four-plate system P,P,P,P,? (d) What is the chargeon P?421 31 4P1P2 | P312.0 V|Figure P26.554) E5 Four parallel metal plates Pj, P2, P3, and P4, each ofarea 7.50 cm², are separated successively by a dis-tance d = 1.19 mm as shown in Figure P26.55. PlateP, is connected to the negative terminal of a battery,and P, is connected to the positive terminal. The2

The capacitor is a device that stores energy in the form of an electric field. When voltage is applied across the capacitor the capacitor gets charged, and the charge is proportional to the applied potential.The electric field is stored as the dipoles are arranged in the space between the terminals. The proportionality constant is the capacitance. Capacitance is measured in SI-derived unit of Farad, ie. F. Usually farad is a very big unit so smaller units are generally used like nano-Farad, pico-Farad, micro-Farad, etc. Discalaimer: You have posted a question with multiple subparts. So, we will only solve the first 3 subparts. If you want other subparts to be questioned please repost the question and mention the subpart you want us to answer. (a) We have to calculate the capacitance of P1P2P3 plate system. The diagram that best represents the case. Thus the capacitors are parallel to each other. C13=C12+C23 Now, for a parallel plate capacitor. C=ε0Ad The total capacitance. C13=2ε0AdC13=8.84×10-12×7.5×10-41.19×10-3C13=5.57 pF (b) The charge on plate P2. Q=CVQ=66.84×10-12 C (c) We have to calculate the capacitance of P1P2P3P4 plate system. The capacitance will be the following. C14=C12+C23+C34C14=8.355 pF