Based on the thermodynamic properties provided for water, determine the amount of energy released for 50.00 g of water to go from 62.0 °C to -17.0 °C. Property Melting point Boiling point AHtus AHvap Cp (s) Cp (1) Cp (8) Value 0.0 100.0 6.01 40.67 37.1 75.3 33.6 Units °C °C kJ/mol kJ/mol J/mol. °C J/mol °C J/mol °C

Based on the thermodynamic properties provided for water, determine the amount of energy released for 50.00 g of water to go from 62.0 °C to -17.0 °C. Property Melting point Boiling point AHtus AHvap Cp (s) Cp (1) Cp (8) Value 0.0 100.0 6.01 40.67 37.1 75.3 33.6 Units °C °C kJ/mol kJ/mol J/mol. °C J/mol °C J/mol °C

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Based on the thermodynamic properties provided for water, determine the amount of energy needed for 2.20 kg of water to go from -14.0 °C to 74.0 °C. 6.50 Property Melting point Boiling point AHfus AHvap Cp (s) Cp (1) Cp (g) kJ Value 0.0 100.0 6.01 40.67 37.1 75.3 33.6 Units °C °℃ kJ/mol kJ/mol J/mol • °C J/mol • °C J/mol • °C
Based on the thermodynamic properties provided for water, determine the amount of energy needed for 2.20 kg of water to go from -17.0 °C to 78.0 °C. Property Melting point Boiling point AHfus AHvap C(s) 5(1) 5 (8) kJ Value 0.0 100.0 6.01 40.67 37.1 75.3 33.6 Units °C °C kJ/mol kJ/mol J/mol - °C J/mol · °C J/mol · °C
Chemistry written by hand please.
Based on the thermodynamic properties provided for methanol (below), select from the following list the equation(s) necessary to calculate the amount of energy needed for 5.0 kg of methanol to go from -64°C to 88°C. Property Value Units Melting point -94 °C Boiling point 65 °C AHfus 3.18 kJ/mol AHvap 37 kJ/mol 615) 48.7 J/mol.°C Cp (1) 81.1 J/mol.°C 5 (8) 43.8 J/mol °C Choose one or more: A. q = n(43.8 J/mol °C)AT, where AT is negative B. q=n(48.7 J/mol ·°C)AT, where AT is negative C. q= n(81.1 J/mol -°C)AT, where A Tis negative D. q = n(43.8 J/mol °C)AT, where A Tis positive E. q=n(-3.18 kJ/mol) F. q- n(37 kJ/mol) G. q=n(-37 kJ/mol) H. q- n(3.18 kJ/mol) 1.q=n(48.7 J/mol °C)AT, where AT is positive J.q=n(81.1 J/mol °C)AT, where A Tis positive
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