Based on the equations for today's reaction: 2- 2 S₂03² + 1₂ → S406² +21- 2 Cu²+ + 41 → 2 Cul (s) + 1₂ How many moles of copper would be used in a reaction that needed 8 mol of S₂O3²- 2-

complete the balanced molecular chemical equation for the reaction below. if no reaction occurs, write NR after the reaction arrow KOH(aq)+AlCl3(aq)=

Identify the type of chemical equations and balance the given equations below. Fe + CO2 Al + H2SO4 → Al2(SO4)3 + H2 FeO + C →

Classifying Reactions and Balancing Chemical Equations Part A: For each of the chemical reactions that are listed below, balance the chemical equation and then state the type of chemical reaction. 1. - Cu (s) + O₂(g) → CuO (s) Reaction type: 2.H₂O ()→→O₂ (g) + H₂ (B) Reaction type: 3. Fe (s) + H₂O () Fe₂O3 (s) + H₂(g) Reaction type: 5. 4.H₂S (aq) + AsCl3 (aq) →→As2S3 (s) + HCl(aq) Reaction type: CaCO3 (s) → CO₂(g) + Reaction type: 6. C4H10O (g) + O₂(g) →→CO₂(g) + H₂O (c) Reaction type: 7. S8 (s) + Fe (s)→ FeS (s) Reaction type: CaO (s) 8. H₂SO4 (aq) +Al (s) →→Al2(SO4)3 (aq) + H₂(g) Reaction type: 9. H3PO4 (aq) + NH,OH (aq) Reaction type: (NH4)3PO4 (aq) + stei HOH (c) 2017-

Complete (where necessary) and balance the following equation. Write the stoichiometric equation, then write the equation in ionic and net ionic form.  __ Cu(OH)2 (s) → CuO (s) + __________

A chemist goes into the lab and performs an experiment in which a mixture of 8.47 grams of Zn and 6.03 g of sulfur are reacted. Before starting the experiment they perform the following calculations to predict the maximum (theoretical) yield of zinc sulfide that could be produced. First, write a balanced equation: Zn + 2 S → ZnS2 Second, check to see which reagent is limiting: 1 mole Zn 1 mole ZnS, 1 mole Zn 129.4 g ZnS, 1 mole ZnS, 8.47 g Zn × = 16.8 g ZnS, %3D 65.4 g Zn 1 mole ZnS, 129.4 g ZnS, 1 mole ZnS, 1 mole S 6.03 g S × = 12.2 g ZnS, 32.0 g S 2 moles S Since 6.03 g S produces the least amount of ZnS2, the S is limiting! They obtain an actual yield of 8.25 grams of zinc sulfide. Calculate their percent yield to one decimal place.

Choose the correct chemical equation for a combustion reaction. O 2C;Hs + 1102 → 6CO2 + 6H20 O 2C3 H6 + 902 → 6CO2 + 6H2O O 2C;H6 + 902 6CO + 6H2 o O 2C;H6 + 702 → 6CO2 + 6H20