Based on the data shown below, calculate the regression line (each value to two decimal places)y =X +y14642.942.8440.738.134.97.29.88.27.59.25.91025.61121.61218.71317.91414.5Question Help: DVideoSubmit QuestionM

The required regression equation of Y on X is, y=a+bxwhere,a=y-interceptb=slope of the…

Based on the data shown below, calculate the regression line (each value to two decimal places) y% = y 1 46 42.9 42.8 4 40.7 38.1 34.9 29.8 8 27.5 9. 25.9 10 25.6 11 21.6 12 18.7 13 17.9 14 14.5 Question Help: D Video Submit Question 5.

Based on the data shown below, calculate the regression line (each value to two decimal places) y% = y 1 46 42.9 42.8 4 40.7 38.1 34.9 29.8 8 27.5 9. 25.9 10 25.6 11 21.6 12 18.7 13 17.9 14 14.5 Question Help: D Video Submit Question 5.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Based on the data shown below, calculate the regression line (each value to two decimal places)y = x + x y 4 26.54 5 26.95 6 31.56 7 33.97 8 35.18 9 36.29
Find the multiple regression model of the given data: y A B с D E F 8.0 19.6 94.9 5.2 2.3 2.1 29.6 8.3 19.8 89.7 5.2 1.8 2.1 32.4 8.5 19.6 96.2 5.5 2.0 2.1 31.0 8.8 18.6 95.6 5.8 1.9 2.0 32.4 9.0 18.8 86.5 6.4 1.8 2.2 32.6 9.3 20.4 84.5 5.8 2.1 2.1 32.2 9.5 20.8 88.9 5.5 1.9 2.2 31.8 Suppose that the regressors are grouped by Group 1: A, C, and F; and Group 2: B, D, and E. Find the multiple regression model.
Run a regression analysis on the following bivariate set of data with y as the response variable. y 62.8 75.2 60 70.4 59.8 63 59.3 68.5 59 70.3 52.4 50.8 63.4 61.9 70.3 68.1 65.6 69.3 56.8 60.9 67.5 77.5 55.5 57.2 Find the correlation coefficient and report it accurate to three decimal places. What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.) r2 = Based on the data, calculate the regression line (each value to three decimal places) y = Predict what value (on average) for the response variable will be obtained from a value of 52.5 as the explanatory variable. Use a significance level of a = 0.05 to assess the strength of the linear correlation. What is the predicted response value? (Report answer accurate to one decimal place.) y = Submit Question IO 01 100 O Details
Run a regression analysis on the following bivariate set of data with y as the response variable. x y -9.7 -66.2 5.6 28.3 -4.5 11.9 35.6 94.9 15.7 21.1 30.8 86.3 48.7 127.9 13 57.3 35.3 109 23.6 32.4 58 166.3 28.1 64.4 19.1 51.5 25.6 53.3 46.1 186.4 43.5 128 Predict what value (on average) for the response variable will be obtained from a value of 14.8 as the explanatory variable. Use a significance level of α=0.05 to assess the strength of the linear correlation.What is the predicted response value? y =
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Run a regression analysis on the following bivariate set of data with y as the response variable. x y 85.1 61.8 40.6 -11.4 36.9 -15.1 72.5 47.9 62 41.8 74.2 19.4 91.3 55.4 57.7 -2.1 84.5 52.1 94.2 55.2 87.8 83.3 51.3 7.1 58.4 -4.9 72.3 16.7 72.6 35.4 71.3 19.2 64.4 16.7 Verify that the correlation is significant at an α=0.05α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 72.4 on the response variable.What is the predicted explanatory value?x =
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 34.4 51.4 21.3 55.8 42.1 45.1 46 44.3 16.6 64 45.5 45.9 41.8 38.8 20.8 56.6 27.6 52.9 12 66.2 35.6 52.4 21.6 57.4 Predict what value (on average) for the response variable will be obtained from a value of 36.9 as the explanatory variable. Use a significance level of α=0.05α=0.05 to assess the strength of the linear correlation.What is the predicted response value?y = (Report answer accurate to one decimal place.)
Run the Linear Regression Analysis for the following: → Submit Excel FileThe average driving distance (yards) and driving accuracy (percent of drives that land in thefairway) for 8 golfers are recorded in the table below.Rank Driving Distance (yards) Driving Accuracy (%)1 316.3 41.72 304.9 48.83 310.8 42.34 312.5 41.25 294.5 54.76 290.7 54.47 296.9 54.28 295.6 53.9a- Write the equation of a straight-line model relating driving accuracy (y) to drivingdistance (x). Select one of the following:i. Y = β1x + εii. Y = β1x2+ β0iii. Y = β1xiv. Y = β0 + β1x + εb- Fit the model and give the least square prediction equation c- Interpret the estimated y-intercept of the line. Choose the correct answer below:i. Since a drive with 0% accuracy is outside the range of the sample data, the y-intercepthas no practical interpretation.ii. Since a drive with distance 0 yards is outside the range of the sample data, the y-intercept has no practical interpretation.iii. For…
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 57.9 -34.4 16.6 92 40.1 89 55.8 54.5 57.9 27.4 17.3 164.1 65.2 62.4 48.3 51.9 66.2 14.5 70.9 -39.2 57 -90.1 58.5 63 Find the correlation coefficient and report it accurate to three decimal places.r = What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.)r² = %
Write out the regression equation using the information from the table: Variable Est. S.E. t p-value 95% Confidence Interval Race 5.20 1.05 Party 7.54 0.14 7.26, 7.82 Income 0.31 0.65 0.48 -0.96 , 1.58 Intercept 15.00 1.13 13.31 0.000 12.77, 17.18
Run a regression analysis on the following data set with y as the response variable. x y 86.9 31.3 54.8 1.8 87.8 20.1 79.7 25.1 101 41 83 24.2 68.7 28.6 86.7 35.6 93.8 33.6 What is the predicted value of the response variable when the explanatory variable has value 78.87 Round your final answer to 1 decimal place.
Based on the data shown below, calculate the regression line. y 1 4.27 3.64 3 3.31 5.08 5.85 6. 2.42 y = [three decimal accuracy] [three decimal accuracy] 45