Based on all student records at Camford University, students spend an average of 5.80 hours per week playing organized sports. The population's standard deviation is 3.50 hours per week. Based on a sample of 64 students, Healthy Lifestyles Incorporated (HLI) would like to apply the central limit theorem to make various estimates. Required: a. Compute the standard error of the sampling distribution of sample means. (Round your answer to 2 decimal places.) Standard error b. What is the chance HLI will find a sample mean between 5 and 6.6 hours? (Round your z and standard error values to 2 decimal places. Round your intermediate and final answer to 4 decimal places.) Chance c. Calculate the probability that the sample mean will be between 5.4 and 6.2 hours. (Round your z and standard error values to 2 decimal places. Round your intermediate and final answer to 4 decimal places.) Probability

The average annual rainfall in New York City follows a normal distribution with a mean of 49.9 inches and a standard deviation of 9.5 inches. On what percentage of years can we expect there to be between 40.4 and 59.4 inches of rain in New York City? (A) 100% B) 99.7% C) 95% D) 68%

You may need to use the appropriate appendix table or technology to answer this question.   In order to estimate the average time spent per student on the computer terminals at a local university, data were collected for a sample of 81 business students over a one-week period. Assume the standard deviation is 1.4 hours. The standard error is 0.156. Find the approximate margin of error with a 0.95 probability.   a) 0.259 b) 0.310 c) 1.645 d) 1.96

A bottled water distributor wants to determine whether the mean amount of water contained in 1-gallon bottles purchased from a nationally known water bottling company is actually 1 gallon. You know from the water bottling company specifications that the standard deviation of the amount of water is 0.03 gallon. You select a random sample of 45 bottles, and the mean amount of water per 1-gallon bottle is 0.996 gallon. Complete parts (a) through (d) below. a. Is there evidence that the mean amount is different from 1.0 gallon? (Use a = 0.01.) Let u be the population mean. Determine the null hypothesis, Ho, and the alternative hypothesis, H, . Ho: H What is the test statistic? ZSTAT = (Round to two decimal places as needed.) What is/are the critical value(s)? (Use a = 0.01.) (Round to two decimal places as needed. Use a comma to separate answers as needed.) What is the final conclusion? O A. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim that the mean…

A variable of a population has a mean of µ = 82 and a standard deviation of o = 9. a. Identify the sampling distribution of the sample mean for samples of size 81. b. In answering part (a), what assumptions did you make about the distribution of the variable? c. Can you answer part (a) if the sample size is 25 instead of 81? Why or why not? a. What is the shape of the sampling distribution? normal uniform skewed O bimodal What is the mean of the sampling distribution? Hi = (Simplify your answer.) What is the standard deviation of the sampling distribution? (Simplify your answer.) b. In answering part (a), what assumptions did you make about the distribution of the variable? A. It was assumed that the variable was normally distributed. B. No assumptions were made because, for a relatively large sample size, the sampling distribution is normal, regardless of the distribution of the variable under consideratio

The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 50 ounces and a standard deviation of 4 ounces. Use the Standard Deviation Rule, also known as the Empirical Rule (see image below). Do not use normalcdf on your calculator. Suggestion: sketch the distribution in order to answer these questions. a) 95% of the widget weights lie between and b) What percentage of the widget weights lie between 46 and 58 ounces? c) What pagcentage of the widget weights lie below 62 ? % 34% 34% 2.35% 13.5% 2.35% 0.15% 13.5% -35 25 0.15% -1s 1s 25

The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 46 ounces and a standard deviation of 9 ounces. Use the Standard Deviation Rule, also known as the Empirical Rule (see image below). Do not use normalcdf on your calculator. Suggestion: sketch the distribution in order to answer these questions. a) 99.7% of the widget weights lie between b) What percentage of the widget weights lie between 37 and 73 ounces? c) What percentage of the widget weights lie above 28? 0.15% -3s 2.35% -25 13.5% -1s 34% 34% 1s 13.5% 2s 2.35% 3s and 0.15% % %

Esp Heavy children: Are children heavier now than they were in the past? The National Health and Nutrition Examination Survey (NHANES) taken between 1999 and 2002 reported that the mean weight of six-year-old girls in the United States was 49.3 pounds. Another NHANES survey, published in 2008, reported that a sample of 193 six-year-old girls weighed between 2003 and 2006 had an average weight of 52 pounds. Assume the population standard deviation is o =16 pounds. Can you conclude that the mean weight of six-year-old girls in 2006 is different from what it was in 2002? Use the a =0.01 level of significance and the critical value method. 00 Part: 0/ 5 Part 1 of 5 (a) State the appropriate null and alternate hypotheses. H.: OD O=0 dl. H : This hypothesis test is a (Choose one) test. 00

The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 60 ounces and a standard deviation of 3 ounces. Use the Standard Deviation Rule, also known as the Empirical Rule (see image below). Do not use normalcdf on your calculator. Suggestion: sketch the distribution in order to answer these questions. a) 99.7% of the widget weights lie between b) What percentage of the widget weights lie between 57 and 69 ounces? c) What percentage of the widget weights lie above 54 ? 0.15% -3s 2.35% -25 13.5% -1s 34% 34% 1s 13.5% 2s 2.35% 3s and 0.15% % %

In the US women between the ages of 18 to 50 have shoe sizes that approximately follow a normal distribution.  The approximate mean is shoe size 8.43 and the standard deviation is 1.35. Find the 90th percentile of this distribution, write the calculator function used to compute the result, and interpret it in a complete sentence.