Base your answers to questions 94 the information and diagram below. A 1.00-kilogram sphere M, suspended by a string from point P, is lifted to a height h. The sphere is released and passes through the lowest point in its swing at a speed of 10.0 meters per second. [Neglect friction.] 10.0 m M. 1.00 kg 94. Calculate the height from which the sphere was released. 95. Calculate the magnitude of the centripetal force on the sphere as it passes through the lowest point in its swing. 96. The magnitude of the centripetal force on the sphere could be halved as it passes through the lowest point in its swing by doubling the (1) weight of the sphere, only (2) length of the string, only (3) height h and the weight of the sphere (4) the length of the string and height h

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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please help with questions 94,95,96 and 97 altogether because they are for one whole problem
97. Compared to the sphere's speed through the
when released from 2h would be
h, the sphere's speed through the lowest point
lowest point of its swing when released from
(1) lower
(2) greater
(3) the same
Transcribed Image Text:97. Compared to the sphere's speed through the when released from 2h would be h, the sphere's speed through the lowest point lowest point of its swing when released from (1) lower (2) greater (3) the same
Base your answers to questions 94 through
the information and diagram below.
A 1.00-kilogram sphere M, suspended by a string
from point P, is lifted to a height h. The sphere is
released and passes through the lowest point in
its swing at a speed of 10.0 meters per second.
[Neglect friction.]
10.0 m
M.
1.00 kg
94. Calculate the height from which the sphere was
released.
95. Calculate the magnitude of the centripetal force
on the sphere as it passes through the lowest
point in its swing.
96. The magnitude of the centripetal force on the
sphere could be halved as it passes through the
lowest point in its swing by doubling the
(1) weight of the sphere, only
(2) length of the string, only
(3) height h and the weight of the sphere
(4) the length of the string and height h
Transcribed Image Text:Base your answers to questions 94 through the information and diagram below. A 1.00-kilogram sphere M, suspended by a string from point P, is lifted to a height h. The sphere is released and passes through the lowest point in its swing at a speed of 10.0 meters per second. [Neglect friction.] 10.0 m M. 1.00 kg 94. Calculate the height from which the sphere was released. 95. Calculate the magnitude of the centripetal force on the sphere as it passes through the lowest point in its swing. 96. The magnitude of the centripetal force on the sphere could be halved as it passes through the lowest point in its swing by doubling the (1) weight of the sphere, only (2) length of the string, only (3) height h and the weight of the sphere (4) the length of the string and height h
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