balanced_recursive(root): """ O(N) solution """ return -1 != __get_depth(root) def __get_depth(root): """ return 0 if unbalanced else depth + 1 """ if root is None: return 0
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def is_balanced(root):
return __is_balanced_recursive(root)
def __is_balanced_recursive(root):
"""
O(N) solution
"""
return -1 != __get_depth(root)
def __get_depth(root):
"""
return 0 if unbalanced else depth + 1
"""
if root is None:
return 0
left = __get_depth(root.left)
right = __get_depth(root.right)
if abs(left-right) > 1 or -1 in [left, right]:
return -1
return 1 + max(left, right)
# def is_balanced(root):
# """
# O(N^2) solution
# """
# left = max_height(root.left)
# right = max_height(root.right)
# return abs(left-right) <= 1 and is_balanced(root.left) and
# is_balanced(root.right)
# def max_height(root):
# if root is None:.
Step by step
Solved in 3 steps with 1 images
- Use the template below: def createList(n): #Base Case/s #ToDo: Add conditions here for base case/s #if <condition> : #return <value> #Recursive Case/s #ToDo: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once all ToDo is completed return [] def removeMultiples(x, arr): #Base Case/s #TODO: Add conditions here for your base case/s #if <condition> : #return <value> #Recursive Case/s #TODO: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once you've completed all ToDo return [] def Sieve_of_Eratosthenes(list): #Base Case/s if len(list) < 1 : return list #Recursive Case/s else: return [list[0]] + Sieve_of_Eratosthenes(removeMultiples(list[0], list[1:])) if __name__ == "__main__": n = int(input("Enter n: "))…In a recursive solution, the _____ case is easily calculated, provides a stopping criterion, and prevents infinite loops. In the _____ case, the solution calls itself.Lab Goal : This lab was designed to teach you more about recursion. Lab Description : luckyThrees will return a count of the 3s in the number unless the 3 is at the start. A 3 at the start of the number does not count. /* luckyThrees will return the count of 3s in the number* unless the 3 is at the front and then it does not count* 3 would return 0* 31332 would return 2* 134523 would return 2* 3113 would return 1* 13331 would return 3* 777337777 would return 2* the solution to this problem must use recursion*/public static int luckyThrees( long number ){} Sample Data : 331332134523311313331777337777 Sample Output : 022132
- Python Test Program: import recursive_functionsimport mathdef main():# Test factorialprint('Testing factorial.')assert recursive_functions.factorial(0) == 1assert recursive_functions.factorial(1) == math.factorial(1)== 1assert recursive_functions.factorial(2) == math.factorial(2)== 2assert recursive_functions.factorial(5) == math.factorial(5)== 120assert recursive_functions.factorial(7) == math.factorial(7)== 5040print('All tests pass for `factorial` ()\n')# Test sum_recursivelyprint('Testing sum_recursively.')assert recursive_functions.sum_recursively(0) == 0assert recursive_functions.sum_recursively(1) ==sum(range(1+1)) == 1assert recursive_functions.sum_recursively(2) ==sum(range(2+1)) == 3assert recursive_functions.sum_recursively(10) ==sum(range(10+1)) == 55print('All tests pass for `sum_recursively` () ')# Test sumlist_recursively(l)print('Testing sumlist_recursively.')assert recursive_functions.sumlist_recursively([1,2,3])…8. Know how to do these, to trace functions like these and to debug functions like these: // recursive power , compute xn int exp(int x, int n){ if(n== return return *exp( ); } void main(){ int a,b; cin >>a>>b; cout>a; rev_print(a); }A recursive function’s solvable problem is known as its __________. This causes the recursion to stop.
- CodeWorkout Gym Course Search exercises... Q Search kola shreya@colum X459: Review- Fibonacci In mathematics, the Fibonacci numbers are the numbers in the following integer sequence, characterized by the fact that every number after the first two is the sum of the two preceding ones: e, 1, 1, 2, 3, 5, 8, 13, Write a recursive function that the returns the nth fibonacci number. Examples: fibonacci(0) -> 0 fibonacci(1) -> 1 fibonacci(7) -> 13 Your Answer: 1 public int fibonacci(int n) { 2 3} 4 CodeWorkout © Virginia Tech About License Privacy ContactConsider the following function: void fun_with_recursion(int x) { printf("%i\n", x); fun_with_recursion(x + 1); } What will happen when this function is called by passing it the value 0?Hef sharks_minnows (minnows, sharks): shark_count = 0 minnow_count = len (minnows) for i in range(minnow_count): curr_shark_height = minnows [i] if curr_shark_height is not None: minnows [i] = None for j in range (i + 1, minnow_count): if minnows [j] == curr_shark_height: minnows [j] = None curr_shark_height -- 1 shark_count += 1 return shark_count <= sharks The provided code is imperfect, in that it sometimes returns True when it should return False, and sometimes returns False when it should return True. (a) Provide an example of a function call where the provided code will correctly return True (i.e. a True Positive) (b) Provide an example of a function call where the provided code will correctly return False (i.e. a True Negative) (c) Provide an example of a function call where the provided code will incorrectly return True (i.e. a False Positive) (d) Provide an example of a function call where the provided code will incorrectly return False (i.e. a False Negative)
- Magic Number Code question::-1.A number is said to be a magic number,if summing the digits of the number and then recursively repeating this process for the given sumuntill the number becomes a single digit number equal to 1. Example: Number = 50113 => 5+0+1+1+3=10 => 1+0=1 [This is a Magic Number] Number = 1234 => 1+2+3+4=10 => 1+0=1 [This is a Magic Number] Number = 199 => 1+9+9=19 => 1+9=10 => 1+0=1 [This is a Magic Number] Number = 111 => 1+1+1=3 [This is NOT a Magic Number].A recursive function typically has two components: one that provides a means for the recursion to terminate by testing for a(n)____________ case, and one that expresses the problem as a recursive call for a slightly simpler problem than the original call.'''Given code (copy-paste): Problem (see pic): def createList(n): #Base Case/s #ToDo: Add conditions here for base case/s #if <condition> : #return <value> #Recursive Case/s #ToDo: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once all ToDo is completed return [] def removeMultiples(x, arr): #Base Case/s #TODO: Add conditions here for your base case/s #if <condition> : #return <value> #Recursive Case/s #TODO: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once you've completed all ToDo return [] def Sieve_of_Eratosthenes(list): #Base Case/s if len(list) < 1 : return list #Recursive Case/s else: return [list[0]] + Sieve_of_Eratosthenes(removeMultiples(list[0], list[1:])) if __name__ == "__main__": n =…